๐ Class IXScience๐งฉ WorksheetChapter 6: How Forces Affect Motion
How Forces Affect Motion Worksheet Class 9 (PDF+Answers)
How Forces Affect Motion Worksheet Class 9 - 68 questions with answers & free PDF on friction, inertia, momentum and Newton's laws.
This free Worksheet for CBSE Class IX Science, Chapter 6: How Forces Affect Motion, contains a structured worksheet with MCQs, short answer, case-based and HOTS questions in one place. It has been prepared by Sumeet Sahu at Unique Study Point, Indore, strictly following the latest NCERT syllabus for Session 2026-27.
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How Forces Affect Motion โ Class 9
UNIQUE STUDY POINT BY SUMEET SAHU
How Forces Affect Motion
Class 9 · Science (Exploration) · Practice Worksheet with Solutions
68 Questions
Tap any question's "Show Answer" button to reveal the full step-by-step solution.
Two masses m and 2m are dropped from a certain height 'h'. Then on reaching the ground,MCQ
a) K.E. of the heavier is more than that of the lighter.
b) K.E. of the heavier is 4 times the K.E. of the lighter
c) K.E. of the lighter is 4 times the K.E. of the heavier
d) K.E. of them will be equal
✓ Correct Answer: (a) K.E. of the heavier is more than that of the lighter.
P.E. of object 1 (mass m) = mgh. P.E. of object 2 (mass 2m) = 2mgh.
On reaching the ground, the P.E. of both objects gets completely transformed into K.E.
Therefore, K.E. of object 2 > K.E. of object 1.
2
When a body is whirled in a circle the work done by the centripetal force is:MCQ
a) negative
b) positive
c) infinite
d) zero
✓ Correct Answer: (d) zero
Work done is defined as the distance an object is moved in the direction of the force applied. Since the centripetal force acts perpendicular to the velocity (direction of motion), the work done is zero.
3
Match the columns and select the correct option from the codes given here.
(a) Work done by all the forces
?
(b) Work done by conservative forces
?
(c) Work done by external forces
?
(d) Work done in uniform velocity
?
Options: (i) Change in potential energy (ii) Change in kinetic energy (iii) Change in mechanical energy (iv) Zero
Work by all forces changes kinetic energy; work by conservative forces changes potential energy; work by external forces changes mechanical energy; and work done during uniform velocity motion is zero (no change in KE).
4
A person uses an inclined ramp to raise an object over a step 30 cm high. The ramp has a width of 40 cm. What is the mechanical advantage of this ramp?MCQ
a) 1.33
b) 0.75
c) 2.00
d) 1.67
✓ Correct Answer: (d) 1.67
Given height (h) = 30 cm, width (base) = 40 cm.
Using Pythagoras theorem for the ramp length L: L² = h² + width² = 30² + 40² = 900 + 1600 = 2500. So L = √2500 = 50 cm.
Mechanical advantage (MA) = L/h = 50/30 = 1.67.
5
Statement 1: If a light body and a heavy body possess the same momentum, the lighter body will possess more kinetic energy. Statement 2: The kinetic energy of a body varies as the square of its velocity.MCQ
a) Statement 1 is true but statement 2 is false.
b) Both statements 1 and 2 are false.
c) Both statements 1 and 2 are true and statement 2 is the correct explanation of statement 1.
d) Both statements 1 and 2 are true but statement 2 is not the correct explanation of statement 1.
✓ Correct Answer: (d) Both statements 1 and 2 are true but statement 2 is not the correct explanation of statement 1.
Relation between momentum and KE: p = √(2mEk). If mass decreases (for constant momentum), KE increases accordingly — this is what explains Statement 1, not the fact that KE ∝ v².
Also, Ek = ½mv², so Ek ∝ v² is a true but separate fact (Statement 2).
6
When you push a wheelchair and its displacement is in the same direction as your applied force, what type of work are you doing on the wheelchair?MCQ
a) Negative work
b) Zero work
c) Work of friction
d) Positive work
✓ Correct Answer: (d) Positive work
When the displacement is in the same direction as the applied force, the work done on the object is positive.
7
A jet aircraft of mass 15000 kg lands on an aircraft carrier. A hook on the tail catches a wire, exerting a constant backward force of 367500 N and stopping the jet within 100 m. What was the initial velocity of the aircraft just before the wire caught the hook?MCQ
a) 150 m/s
b) 30 m/s
c) 100 m/s
d) 70 m/s
✓ Correct Answer: (d) 70 m/s
Given: m = 15000 kg, F = 367500 N, s = 100 m. Work done by the (backward) force = −367500 × 100 = −36,750,000 J.
By the work-energy theorem: −½mv² = −36,750,000. So ½ × 15000 × v² = 36,750,000.
v² = 36,750,000/7500 = 4900. v = √4900 = 70 m/s.
8
A vehicle with mass 'm' and initial velocity 'v' has a kinetic energy of (1/2)mv². If its velocity doubles to '2v', what will its new kinetic energy be?MCQ
a) (1/2)mv²
b) 4 × (1/2)mv²
c) mv²
d) 2mv²
✓ Correct Answer: (b) 4 × (1/2)mv²
Initial KE = ½mv². If velocity doubles to 2v, new KE = ½m(2v)² = ½m(4v²) = 4 × ½mv².
Thus, the new kinetic energy will be 4 times the original value.
9
What is the SI unit of power?MCQ
a) Watt
b) Joule
c) Newton
d) Horsepower
✓ Correct Answer: (a) Watt
The SI unit of power is the watt (W).
10
Two inclined frictionless tracks, one gradual and the other steep meet at point A from where two stones (I and II) are allowed to slide down from rest, one on each track as shown in figure. Which of the following statements is correct?
Two inclined tracks AB and AC meeting at point A, with stones I and II sliding down, height h shown
MCQ
a) Both the stones reach the bottom at the same time but not with the same speed.
b) Both the stones reach the bottom with the same speed and stone I reaches the bottom earlier than stone II.
c) Both the stones reach the bottom with the same speed and stone II reaches the bottom earlier than stone I.
d) Both the stones reach the bottom at different times and with different speeds.
✓ Correct Answer: (c) Both the stones reach the bottom with the same speed and stone II reaches the bottom earlier than stone I.
AB and AC are two smooth planes inclined at different angles. Since the height of both planes is the same, both stones reach the bottom with the same speed (v = √2gh, so v1 = v2).
Acceleration a1 = g sinθ1, a2 = g sinθ2. Since θ2 > θ1, a2 > a1.
Using v = u + at: t1 = v1/a1, t2 = v2/a2. Since a2 > a1, t2 < t1. Hence, stone II takes less time to reach the bottom.
11
The potential energy of a body is by virtue of its ________.MCQ
a) power
b) energy
c) direction
d) position
✓ Correct Answer: (d) position
The energy possessed by an object because of its position is called potential energy.
12
If the force applied on the body distances the body in the opposite direction of force applied then work done is:MCQ
a) Zero
b) Positive
c) Negative
d) Constant
✓ Correct Answer: (c) Negative
When force is applied in the direction of displacement, work done is positive (W = F×s). When force is applied in the opposite direction, work done is negative (W = −F×s).
13
Why is it common to define an object that does not move as having zero kinetic energy?MCQ
a) Mass is zero at rest.
b) Energy converts to heat.
c) No motion, so no KE.
d) KE irrelevant at rest.
✓ Correct Answer: (c) No motion, so no KE.
Kinetic energy is the energy of motion, mathematically dependent on velocity. If an object does not move, its velocity is zero, hence its kinetic energy is zero.
14
To observe and compare the pressure exerted by solid iron cuboid, a student marked all the faces of cuboid from 1 to 6. After doing the experiment with all faces of cuboid, he observed thatMCQ
a) adjacent faces of cuboid exerted the same pressure
b) opposite parallel faces of cuboid exerted unequal pressure on the sand
c) opposite parallel faces of the cuboid exerted some pressure on the sand
d) all the faces of cuboid exerted same pressure on the sand
✓ Correct Answer: (c) opposite parallel faces of the cuboid exerted some pressure on the sand
Since force per unit area (pressure) remains the same for opposite parallel faces, the same conclusion is drawn — both exert equal pressure.
15
What does the work-energy theorem state regarding the work done by a force on an object?MCQ
a) Equals potential energy.
b) Equals initial velocity.
c) Equals change in energy.
d) Equals mass.
✓ Correct Answer: (c) Equals change in energy.
From the work-energy theorem, the work done by the force acting on the object translates into the change in the energy of the object.
16
What must occur for work to be done on an object?MCQ
a) The object must gain heat.
b) Force applied with displacement.
c) Only a force must be applied.
d) Only a displacement must occur.
✓ Correct Answer: (b) Force applied with displacement.
Work is done when a force is applied and an object is displaced.
17
A person applies an upward force of 200 N to lift an object. If the object is displaced by 1.5 m in the direction of the force, calculate the work done.MCQ
a) 150 J
b) 200 J
c) 133.33 J
d) 300 J
✓ Correct Answer: (d) 300 J
Given: F = 200 N, s = 1.5 m. Using W = F × s: W = 200 × 1.5 = 300 J.
18
A body is falling from a height h. After it has fallen a height h/2, it will possessMCQ
a) half potential and half kinetic energy
b) only potential energy
c) more kinetic and less potential energy
d) only kinetic energy
✓ Correct Answer: (a) half potential and half kinetic energy
At height h: KE = 0, PE = mgh. At height h/2: PE = mg(h/2) = mgh/2.
Using v² = 2g(h/2) = gh, so KE = ½mv² = ½m(gh) = mgh/2.
So at h/2, the body has equal (half-half) potential and kinetic energy.
19
A ball dropped from a height of 10 m. If the energy of the ball reduces by 40% after striking the ground, how much high can the bounce back? (g = 10 m/s²)MCQ
a) 3 m
b) 6 m
c) 5 m
d) 0 m
✓ Correct Answer: (b) 6 m
Energy = mgh = m × 10 × 10 = 100m J.
Energy reduced by 40%, so remaining energy = 60m J.
60m = m × 10 × h′ ⇒ h′ = 6 m.
20
What is the primary factor determining the depth of the depression created when a ball is dropped into sand from different heights?MCQ
a) The type of sand.
b) The height from which the ball is dropped.
c) The color of the ball.
d) The shape of the ball.
✓ Correct Answer: (b) The height from which the ball is dropped.
The depression is deepest when the ball is dropped from the greatest height, since a greater height leads to greater potential energy and thus a deeper depression.
21
In the activity shown below, more impression will be made by the cuboid in the sand in case of
Activity (i): cuboid standing on larger face; Activity (ii): cuboid standing on smaller face, both on loose sand
MCQ
a) neither in activity (i) nor in activity (ii)
b) activity (ii) only
c) activity (i) only
d) both activities (i) and (ii)
✓ Correct Answer: (b) activity (ii) only
More impression will be made by the cuboid in activity (ii), since pressure P ∝ 1/Area — a smaller contact area (as in activity ii) results in greater pressure and a deeper impression.
22
Match the following with the correct response.
(a) Battery
?
(b) Bulb
?
(c) Steam engine
?
(d) Microphone
?
Options: (i) Electrical energy converts into light energy (ii) Sound energy converts into electrical energy (iii) Steam energy converts into mechanical energy (iv) Chemical energy converts into electrical energy
In a Battery, chemical energy converts into electrical energy.
In a Bulb, electrical energy converts into light energy.
In a Steam engine, steam energy converts into mechanical energy.
In a Microphone, sound energy converts into electrical energy.
23
Match the following columns with the correct response.
(1) Kinetic energy
?
(2) Potential energy
?
(3) Work
?
(4) Power
?
Options: (A) Energy due to position (B) The rate of doing work (C) Force displaces an object in the direction of force (D) Energy due to motion
MCQ
a) 1-D, 2-A, 3-C, 4-B
b) 1-B, 2-D, 3-A, 4-C
c) 1-C, 2-B, 3-D, 4-A
d) 1-A, 2-C, 3-B, 4-D
✓ Correct Answer: (a) 1-D, 2-A, 3-C, 4-B
Kinetic energy is the energy of motion. Potential energy is energy due to position.
Work is defined as a force acting upon an object to cause a displacement. Power is the rate of doing work.
24
Match the following with correct response.
(1) Velocity effects
?
(2) Maximum work done
?
(3) Work done is zero
?
(4) Work done, when force act obliquely
?
Options: (A) Energy (B) 90° (C) 0° (D) F × S × cosθ
MCQ
a) 1-B, 2-D, 3-A, 4-C
b) 1-C, 2-B, 3-D, 4-A
c) 1-D, 2-A, 3-C, 4-B
d) 1-A, 2-C, 3-B, 4-D
✓ Correct Answer: (d) 1-A, 2-C, 3-B, 4-D
As the velocity of an object increases, its Kinetic energy also increases (velocity effects → energy).
W = F×S×cosθ. At θ=0° (cos0°=1), W=F×S, meaning maximum work is done.
At θ=90° (cos90°=0), W=0, meaning zero work is done. When force acts obliquely, general formula W = F×S×cosθ applies.
25
When a coil spring is compressed, the work is done in the spring. The elastic potential energy ________.MCQ
a) disappears
b) decreases
c) remains unchanged
d) increases
✓ Correct Answer: (d) increases
When we compress the spring, potential energy increases: U = ½kx², where x is compression. As x increases, U increases.
26
When a body is partly or wholly immersed in a ________ experiences an ________.MCQ
a) fluid, buoyancy
b) fluid, upthrust
c) buoyancy, fluid
d) fluid, fluid
✓ Correct Answer: (b) fluid, upthrust
A fluid exerts an upward force on a body if it is partly or wholly submerged, because the deeper into a fluid you go, the greater the pressure, and this pressure difference between top and bottom produces an upward force called upthrust.
27
Statement A: An aeroplane flying at an altitude possesses only K.E. Statement B: An aeroplane flying at an altitude possesses both K.E and P.E. Which of the two statement is true?MCQ
a) statement A
b) statement B
c) neither A nor B
d) both A and B
✓ Correct Answer: (b) statement B
An aeroplane in flight has both kinetic energy (since it is moving) and potential energy (since it is displaced above the ground at some height).
28
When a ball thrown upwards reaches its highest point, tick which of the following statement(s) are correct?
The force acting on the ball is zero.
The acceleration of the ball is zero.
Its kinetic energy is zero.
Its potential energy is maximum
MCQ
a) Both i and ii
b) Both iii and iv
c) All of these
d) Both ii and iii
✓ Correct Answer: (b) Both iii and iv
At the highest point, velocity becomes zero instantaneously, so kinetic energy = 0 (iii is correct).
At the same point, the height is maximum, so potential energy is maximum (iv is correct). (The force of gravity and acceleration due to gravity remain acting even at the highest point, so i and ii are incorrect.)
29
Find the incorrect statement A. The P.E. of a freely falling object increases progressively. B. Body at rest may possess energy. C. There is no transfer of energy between you and the rock when you push a huge rock and fail to move it. D. K.E. is converted into heat and sound energy when a freely falling object eventually stops on reaching the ground.MCQ
a) A
b) B
c) C
d) D
✓ Correct Answer: (a) A
When an object starts to fall freely, its K.E. increases while its P.E. decreases (not increases), keeping total mechanical energy constant. So statement A is incorrect.
30
When an object starts to fall freely, which statement is incorrect about it? A. Its potential energy is increased and kinetic energy is decreased B. Its kinetic energy is increased and potential energy is decreased C. Potential energy remains unchanged D. Kinetic energy remains unchangedMCQ
a) A, C and D
b) B and C
c) A and D
d) A, B, C and D
✓ Correct Answer: (a) A, C and D
When an object falls freely, K.E. increases with a decrease in potential energy, and total mechanical energy remains constant. So statements A, C, and D are incorrect, and only B is correct.
31
To observe and compare the pressure exerted by the solid iron cuboid on the sand, two students take the different solid iron cuboid having the same weight but different dimensions. After performing the experiment:MCQ
a) the same conclusion is drawn by them
b) a different conclusion is drawn by them
c) none of the students draw any conclusion
d) the conclusion can be determined by making the dimension the same
✓ Correct Answer: (a) the same conclusion is drawn by them
Opposite parallel faces of cuboids have the same surface area of contact, so the general conclusion about pressure relationships (P ∝ 1/A) is the same regardless of dimension differences.
32
To observe and compare the pressure exerted by solid iron cuboid in its upright position, student 'A' placed the cuboid gently on the loose sand while 'B' placed it on the surface of the tabletop. Who will observe the exerted pressure by the cuboid easily?MCQ
a) Neither A nor B
b) Both students A and B
c) Student A only
d) Student B only
✓ Correct Answer: (c) Student A only
In both cases, the cuboid will exert the same pressure, but the observation (visible impression/depression) will be made only by student A, since loose sand deforms visibly under pressure while a rigid tabletop does not.
33
Assertion (A): A winded toy car, when placed on floor, starts moving. Reason (R): Toy car has kinetic energy stored in it which facilitates its motionAssertion-Reason
a) Both A and R are true and R is the correct explanation of A.
b) Both A and R are true but R is not the correct explanation of A.
c) A is true but R is false.
d) A is false but R is true.
✓ Correct Answer: (c) A is true but R is false.
When a toy car is wound up, work done on it gets stored as elastic potential energy (not kinetic energy). When placed on the ground, this potential energy converts into kinetic energy and facilitates its motion. So R (which says kinetic energy is stored) is false.
34
Assertion (A): The kinetic energy, with any reference, must be positive. Reason (R): It is because, in the expression for kinetic energy, the velocity appears with power 2 and mass is a scalar quantity.Assertion-Reason
a) Both A and R are true and R is the correct explanation of A.
b) Both A and R are true but R is not the correct explanation of A.
c) A is true but R is false.
d) A is false but R is true.
✓ Correct Answer: (a) Both A and R are true and R is the correct explanation of A.
Since mass (scalar, always positive) is multiplied with velocity squared (always non-negative), kinetic energy = ½mv² is always positive, and R correctly explains why A is true.
35
Assertion (A): No work is done when a woman carrying a load on her head, walks on a level road with a uniform velocity. Reason (R): No work is done if force is perpendicular to the direction of displacement.Assertion-Reason
a) Both A and R are true and R is the correct explanation of A.
b) Both A and R are true but R is not the correct explanation of A.
c) A is true but R is false.
d) A is false but R is true.
✓ Correct Answer: (a) Both A and R are true and R is the correct explanation of A.
Work done W = F·ds = Fds cosθ = 0 when θ=90°. Since the force applied (upward, against gravity) is perpendicular to horizontal displacement, no work is done — R correctly explains A.
36
Assertion (A): Work done by the gravitational force through a certain distance is constant irrespective of the fact that the body has a uniform or accelerated motion. Reason (R): Gravitational force is a conservative force.Assertion-Reason
a) Both A and R are true and R is the correct explanation of A.
b) Both A and R are true but R is not the correct explanation of A.
c) A is true but R is false.
d) A is false but R is true.
✓ Correct Answer: (b) Both A and R are true but R is not the correct explanation of A.
Work done by gravitational force through a distance h is always mgh, regardless of the type of motion — true. Gravitational force is indeed conservative — also true, but this fact doesn't directly explain why the work is independent of the type of motion (uniform/accelerated).
Section B · Short Answer Questions (Q37–Q48)
2 Marks each
37
State whether the given statement is True or False:
Energy is the ability to do work.
Work done by a force can be positive, negative, or zero.
(a) True.
(b) True.
38
Can any object have mechanical energy even if its momentum is zero? Explain.
Yes, mechanical energy comprises both potential energy and kinetic energy.
Zero momentum means that velocity is zero. Hence, there is no kinetic energy, but the object may still possess potential energy.
39
Define power in physics and write the formula used to calculate average power.
Power is defined as the rate at which work is done or energy is transferred. It tells us how quickly a task is completed.
P = W/t
Power is equal to the total work done divided by the time taken to do that work.
40
In one of their fastest deliveries, an Indian cricketer bowled a cricket ball with an approximate mass of 0.2 kg at a velocity of about 154.8 km h−1. Calculate the kinetic energy of the ball at the time of its delivery.
Mass of the cricket ball = 0.2 kg. Velocity = 154.8 km/h ≈ 43 m/s.
K = ½mv²
K = ½ × 0.2 × (43)² = 184.9 J.
41
What is the relationship between the commercial unit and SI unit of energy?
Commercial unit of energy = kilowatt hour (kWh). SI unit of energy = Joule (J).
1 kWh = 1 kW × 1 h = 1000 W × 3600 s = 1000 Js−1 × 3600 s = 3,600,000 J = 3.6 × 106 J.
✓ 1 kWh = 3.6 × 10⁶ J
42
Write an expression for the kinetic energy of an object.
K.E. = ½mv²
Where K.E. is the kinetic energy of an object, 'm' is the mass of the object, and 'v' is its velocity.
43
Why cutting instruments are sharpened?
All cutting instruments such as blades, axes etc. are sharpened so that the area of cross-section decreases, and hence the pressure exerted by them increases.
Thus they can easily penetrate a given surface.
44
After taking a catch, a fielder threw the cricket ball of mass 200 g high up in the air about 10 m above the ground in celebration. How much potential energy does the ball have when the ball reaches its maximum height? Assume g = 10 m s−2.
U = mgh
mgh = 0.2 kg × 10 m s−2 × 10 m = 20 J.
45
A body moves along a circular path. How much work is done in doing so? Explain.
In the case of a body moving along a circular path, the centripetal force is always along the radius, while displacement is tangential.
Hence, work done W = Fs cos90° = 0, as the angle between F and s is 90°.
46
A person holds a bundle of hay over his head for 30 minutes and gets tired. Has he done some work or not? Justify your answer.
When a person holds a bundle of hay over his head, he applies a force in the upward direction, but there is no displacement of the bundle (it's held stationary).
W = F × s cosθ = F × 0 = 0. No work is done, even though he feels tired.
47
It is possible that an object is in the state of accelerated motion due to external force acting on it, but no work is being done by the force? Explain with example.
Yes, it is possible. This occurs if an object is moving in a circular path, because the force (centripetal) is always acting perpendicular to the direction of displacement (tangential).
Since W = Fs cos90° = 0, no work is done even though the object is accelerating (changing direction).
48
A force of 10 N displaces a body by a distance of 2 m at an angle 60° to its own direction. Find the amount of work done.
W = F × s × cosθ
Given: F = 10 N, s = 2 m, θ = 60°.
W = 10 × 2 × cos60° = 10 × 2 × ½ = 10 J.
Section C · Short Answer Questions – II (Q49–Q59)
3 Marks each
49
Fill in the blanks:
Work done is ________ when the force is in the direction of displacement.
When a body is moved on the ground by applying force, then work is done against ________.
If we push a huge rock and it does not move despite all the effort then work is not done as there is no ________ of the rock.
(a) Positive
(b) Friction
(c) Displacement
50
A crane lifts a mass m to the 10th floor of a building in a certain time. It then raises the same mass to the 20th floor of the same building in double the time. How much more energy and power are required? Assume that the height of all floors is equal.
Let height of each floor = h. Potential energy PE = mgh.
For 20th floor → height = 20h. E2 = mg(20h) = 20mgh. So E2 = 2E1.
Power required
Let time for 10th floor = t, time for 20th floor = 2t.
Power for 10th floor: P1 = 10mgh/t. Power for 20th floor: P2 = 20mgh/2t = 10mgh/t.
So, P2 = P1 (power required stays the same).
✓ Energy required doubles (2E₁); Power required stays the same
51
Explain the relationship between work done on an object and its kinetic energy in both positive and negative work cases.
According to the work-energy theorem, the work done on an object is equal to the change in its kinetic energy.
When positive work is done, the object's kinetic energy increases because the force acts in the direction of motion.
When negative work is done, the kinetic energy decreases as the force opposes motion.
If no work is done, there is no change in kinetic energy, and the object continues moving with the same speed.
52
A student is slowly lifted straight up in an elevator from the ground level to the top floor of a building. Later, the same student climbs the staircase, all the way to the top. Given that the height of the building is h = 72.5 m, acceleration due to gravity is g = 10 m s−2, and student's mass is m = 50 kg.
Find the gain in the potential energy if the student is lifted straight up to the top.
Find the gain in the potential energy when the student climbs the stairs to the same top.
What do you conclude about the dependence of the potential energy on the path taken?
(i) PE = mgh = 50 × 10 × 72.5 = 36,250 J.
(ii) PE = mgh = 50 × 10 × 72.5 = 36,250 J.
(iii) The gain in potential energy is the same in both cases, showing that potential energy depends only on the initial and final positions (height), not on the path taken to reach there.
53
Throughout history, many designs of perpetual machines (using wheels, weights or magnets) have been proposed but none actually work. Why do all real machines eventually slow down and stop? Explain in terms of work and energy.
All real machines slow down and stop because external forces like friction and air resistance do negative work on them.
This means the machine's mechanical energy decreases, and energy is continuously converted into heat and sound.
No machine can perfectly conserve its mechanical energy, since energy is being lost to the surroundings, so the machine gradually loses motion and finally stops.
54
Why is it incorrect to define work only based on effort or tiredness in scientific terms? Explain with an example.
In science, work is not defined by effort or tiredness, but by force causing displacement.
A person may feel tired due to energy used by muscles, but if there is no movement, no work is done scientifically.
Example: When pushing a rigid wall, the person uses energy and feels tired, but the wall does not move. Since displacement is zero, the work done on the wall is also zero, showing the difference between effort and scientific work.
55
A jet aircraft of mass 15000 kg lands on the deck of an aircraft carrier in fig. To stop the aircraft within the short length of the deck a hook on the aircraft's tail is caught in a wire stretched across the deck. The wire exerts an approximately constant backward force of 367500 N and stops the jet within 100 m. What was the velocity of the aircraft just before the wire caught the hook?
Jet aircraft landing on an aircraft carrier deck
Let the aircraft's approach velocity be v. Initial KE = ½ × 15000 × v². Final KE = 0.
The displacement of the aircraft and the force applied by the wire are in opposite directions, so the work done by the wire is negative: W = F × s = 367500 N × (−100 m).
Using work done = change in KE: −½ × 15000 × v² = −(367500 × 100).
v² = (367500 × 2 × 100)/15000 = 4900. v = √4900 = 70 m/s (≈ 252 km/h) towards the aircraft carrier.
56
Figure shows a conveyor belt transporting a package to a raised platform. The belt is driven by a motor.
Conveyor belt with motor transporting a package to a raised platform
State three types of energy, other than gravitational potential energy, into which the electrical energy supplied to the motor is converted.
The mass of the package is 36 kg. Calculate the increase in the gravitational potential energy (p.e.) of the package when it is raised through a vertical height of 2.4 m.
The package is raised through the vertical height of 2.4 m in 4.4 s. Calculate the power needed to raise the package.
Assume that the power available to raise package is constant. A package of mass greater than 36 kg is raised through the same height. Suggest explain the effect of this increase in mass on the operation of the belt.
(i) Kinetic energy of belt/package, heat energy, and sound energy.
(ii) m = 36 kg, h = 2.4 m, g = 10 m/s². G.P.E. = m × g × h = 36 × 10 × 2.4 = 864 J.
(iii) Power = W/t = 864/4.4 = 196.36 W.
(iv) Since power is constant and mass is increased, the increase in potential energy is greater. Also, as mass increases, speed reduces, and hence the time taken by the conveyor is longer.
57
What will be the magnitude of velocity of the child at the bottom of the blue slide?
When the child is at the top of the slide, they have gravitational potential energy due to height.
As the child slides down, potential energy decreases and kinetic energy increases.
At the bottom, almost all the potential energy converts into kinetic energy (assuming negligible friction). Applying conservation of mechanical energy:
mgh = ½mv²
Mass cancels out, giving: v = √2gh, where h = height of slide and g = acceleration due to gravity.
58
Why do you push an object closer to scissors (fulcrum) when you want to cut an object which is hard?
Scissors work as a lever with a fulcrum (pivot point).
When the object is placed closer to the fulcrum, the effort arm becomes longer and the load arm becomes shorter.
This increases the mechanical advantage, making it easier to cut hard objects.
59
Explain how an object gains the ability to do work through energy transfer.
An object gains the capacity to do work when energy is transferred to it by doing work on it.
When a force acts on an object and causes displacement, work is done, and the object gains energy, usually as kinetic or potential energy.
This stored energy enables the object to apply force on another object and cause motion. For example, a moving ball can hit another object and transfer its energy, showing its ability to do work.
Section D · Case Study Based Questions (Q60–Q62)
4 Marks each
60
Case Study: Work is closely related to energy. The work-energy principle states that an increase in the kinetic energy of a rigid body is caused by an equal amount of positive work done on the body by the resultant force acting on that body.
Define potential energy.
Give an example where potential energy is acquired by a body due to a change in its shape.
A skier of mass 50 kg stands at A, at the top of a ski jump. He takes off from A for his jump to B. Calculate the change in his gravitational potential energy between A and B.
Ski jump profile: point A at 75 m, point B at 60 m above ground level
OR — An object of mass, m is moving with a constant velocity, v. How much work should be done on the object in order to bring the object to rest?
(i) Potential Energy is the energy possessed by a body by virtue of its position or shape.
(ii) In a toy car, the wound spring possesses potential energy. When the spring is released, its potential energy changes into kinetic energy, causing the toy car to move.
(iii) Given: m = 50 kg, h1 = 75 m, h2 = 60 m. At A: PE1 = mgh1 = 50×10×75 = 37,500 J. At B: PE2 = mgh2 = 50×10×60 = 30,000 J.
Change in PE = PE1 − PE2 = 37500 − 30000 = 7500 J.
OR
The kinetic energy of an object of mass m moving with velocity v is given by ½mv².
To bring the object to rest, an equal amount of work, i.e. ½mv², is required to be done on the object (as negative work).
✓ (i) Energy due to position/shape (ii) Wound spring (iii) 7500 J (OR: ½mv²)
61
Case Study: Mechanical energy is the total energy possessed by an object due to its motion and position. It is the sum of kinetic energy and potential energy. Kinetic energy depends on the velocity of the object, while potential energy depends on its position, such as height above the ground. When an object is lifted, it gains potential energy, which can later convert into kinetic energy when it falls. This conversion demonstrates the conservation of mechanical energy, where the total energy remains constant if no external forces like friction act.
"Mechanical Energy" infographic — gaining/converting to KE, measured in joules, and conservation of mechanical energy examples
For example, a falling object loses potential energy but gains kinetic energy in equal amount. This principle helps explain many natural phenomena and simplifies calculations by focusing on energy changes rather than forces. Mechanical energy is always measured in joules, and it provides a powerful way to analyse motion without tracking every force involved.
What is mechanical energy? (1)
What are its two components? (1)
How is energy conserved in a falling object? (2) OR — Why is conservation of mechanical energy useful? (2)
(i) Mechanical energy is the total energy of an object due to its motion and position. It is calculated as the sum of kinetic energy and potential energy present in the system.
(ii) The two components of mechanical energy are kinetic energy and potential energy. Kinetic energy depends on motion, while potential energy depends on position, especially height in gravitational fields.
(iii) In a falling object, potential energy decreases as height reduces, while kinetic energy increases due to rising speed. The total mechanical energy remains constant because the loss in potential energy equals the gain in kinetic energy.
OR
Conservation of mechanical energy simplifies problem-solving by avoiding detailed force calculations. It allows us to determine velocity or position by considering energy changes, making it easier to analyse motion in many real-life and physics problems.
✓ (i) KE + PE (ii) Kinetic and Potential energy (iii) PE loss = KE gain
62
Case Study: In physics, work is the energy transferred to or from an object via the application of force along with a displacement. In its simplest form, it is often represented as the product of force and displacement. A force is said to do positive work if (when applied) it has a component in the direction of the displacement of the point of application. A force does negative work if it has a component opposite to the direction of the displacement at the point of application of the force.
Hammer illustrating Potential Energy, Kinetic Energy, and Mechanical Energy states
State the law of conservation of energy. (1)
Define mechanical energy. (1)
Calculate the energy in kWh consumed in 5 hours by four devices of power 600 W each. (2) OR — Can a body have energy, without having momentum? If yes, why? (2)
(i)Law of conservation of energy: The energy in a system can neither be created nor destroyed. It may be transformed from one form to another, but the total energy of the system remains constant.
(ii) The energy possessed by a body due to a displacement caused in it by the application of a force is called mechanical energy.
(iii) Energy = Power × Time = 4 × 600 W × 5 h = (4×600×5)/1000 = 12000/1000 = 12 kWh.
OR
Yes, a body can have energy without possessing momentum. A body may have potential energy and still be at rest, meaning it would have zero momentum and yet still possess energy.
✓ (i) Energy neither created nor destroyed (ii) Energy due to force+displacement (iii) 12 kWh (OR: Yes, via PE)
Section E · Long Answer Questions (Q63–Q68)
5 Marks each
63
Fill in the blanks:
Work done is ________ when the force acts opposite to the direction of displacement.
Suppose a baby is pulling a toy car parallel to the ground. He exerts a force in the direction of ________ of the car.
When a force of 1 newton moves a body through a distance of 1 metre in its own direction, then the work done is known as ________.
The expression for kinetic energy of a body of mass m and velocity v is ________.
The potential energy of an object of mass m at a small height h from the Earth's surface is ________.
(a) Negative
(b) Displacement
(c) 1 joule
(d) ½mv²
(e) mgh
64
a. Give one example of each of the following:
Small mass but high kinetic energy
Large mass but low kinetic energy
b. Prove mathematically that the total mechanical energy of a freely falling body in air is conserved.
(a) Examples
(i) A cricket/hockey ball having small mass which has been hit hard and is travelling fast (possesses high kinetic energy).
(ii) A shot put having large mass thrown by an athlete possesses low kinetic energy.
(b) Proof of conservation of mechanical energy
Let a body of mass m be at height h above the ground at point A. Its K.E. = 0, P.E. = mgh. Total energy at A = 0 + mgh = mgh.
After falling freely through a distance x, at point B: KE at B = mgx, and PE = mg(h−x). Total energy at B = mgx + mg(h−x) = mgh.
When it reaches the ground at point C: v² = u² + 2gh, and since u=0, v² = 2gh. Its KE = ½mv² = ½m(2gh) = mgh, and PE = 0. Total energy at C = mgh + 0 = mgh.
✓ Total energy at A = B = C = mgh, so total mechanical energy is always conserved
65
State the law of conservation of energy.
Illustrate the law of conservation of energy by discussing the energy changes which occur when we draw a pendulum bob to one side and allow it to oscillate.
(i) Energy can neither be created nor destroyed; it may be transformed from one form to another, but the total energy of an isolated system remains constant.
(ii) Pendulum oscillation
Consider a simple pendulum in its mean position P. When pulled to position R, it gains height, so at R it has: maximum potential energy, and zero kinetic energy (held by hand).
When released from R, it moves towards P and velocity increases, so kinetic energy increases at the expense of potential energy. At position P (lowest point), it has: maximum kinetic energy, and zero potential energy.
When it swings from P to Q, it gains height again, so PE increases while velocity (and hence KE) decreases. At Q it has: maximum potential energy, and zero kinetic energy momentarily.
From this example, it is clear that in the pendulum-Earth system, energy is conserved — it is the potential energy which changes into kinetic energy and vice-versa.
66
Briefly describing the gravitational potential energy, deduce an expression for the gravitational potential energy of a body of mass m placed at a height h, above the ground.
When an object is raised through a certain height above the ground, its energy increases because work is done on it against gravity.
The energy present in such an object is called gravitational potential energy — the work done in raising it from the ground to that point against gravity.
Consider a body of mass m at point P on the Earth's surface (PE = 0). To lift it to point Q at height h, we apply a minimum force equal to mg (upward), doing work against gravity.
Work done, W = F × s
As F = mg and s = h, substituting: W = mg × h = mgh.
This work done equals the gain in energy of the body — the potential energy.
✓ Potential energy, PE = mgh
67
Give an example of energy transfer without direct contact between objects.
Describe one method, other than mechanical work, by which energy can be transferred between objects.
(i) Energy can be transferred without direct contact through radiation. For example, the Sun transfers energy to the Earth in the form of heat and light through space, without any physical contact between them.
(ii) Energy can also be transferred as heat. When two objects at different temperatures come into contact, energy flows from the hotter object to the colder one. This process continues until both objects reach the same temperature, known as thermal equilibrium, showing transfer of energy without mechanical work.
68
Illustrate the law of conservation of energy by discussing the energy changes which occur when we draw a pendulum bob to one side and allow it to oscillate. Why does the bob eventually come to rest? What happens to its energy eventually? Is it a violation of the law of conservation of energy?
When the pendulum bob is pulled (say towards left), the energy supplied is stored as P.E. due to its higher position.
When released and moving towards right, its P.E. changes into K.E., such that at the mean position it has maximum K.E. and zero P.E.
As the pendulum moves towards the extreme right, its K.E. changes back into P.E., reaching zero K.E. at the extreme. Moving from this extreme back to mean position, P.E. again changes to K.E. This illustrates the law of conservation of energy.
Why does the bob eventually stop?
Eventually, the bob comes to rest because during each oscillation, a part of its energy is transferred to air (air resistance) and lost in overcoming friction at the point of suspension.
Thus, the energy of the pendulum is dissipated into the surroundings (as heat/sound in air and at the pivot).
✓ Not a violation — the energy merely changes form (to heat/sound) and is not destroyed