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Sound Waves Worksheet Class 9 (PDF + Answers)

Sound Waves Worksheet Class 9 - 69 questions with answers & free PDF on frequency, amplitude, echo, reverberation and SONAR.

This free Worksheet for CBSE Class IX Science, Chapter 10: Sound Waves: Characteristics and Applications, contains a structured worksheet with MCQs, short answer, case-based and HOTS questions in one place. It has been prepared by Sumeet Sahu at Unique Study Point, Indore, strictly following the latest NCERT syllabus for Session 2026-27.

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Sound Waves: Characteristics and Applications โ€” Class 9
UNIQUE STUDY POINT BY SUMEET SAHU

Sound Waves: Characteristics and Applications

Class 9 · Science (Exploration) · Practice Worksheet with Solutions

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Section A · Objective Type Questions (Q1–Q38)

1 Mark each
1
Wave motion transfersMCQ
  • a) energy
  • b) mass
  • c) momentum
  • d) velocity
✓ Correct Answer: (a) energy
  1. 'Wave' refers to different ways energy is transferred. In sound waves, energy is transferred through the vibration of air particles or particles of a solid through which the sound travels.
2
What common characteristic is observed when a rubber band produces sound?MCQ
  • a) It expands in length.
  • b) It vibrates.
  • c) It changes color.
  • d) It heats up significantly.
✓ Correct Answer: (b) It vibrates.
  1. As long as the rubber band is stretched and vibrating, sound is produced. Once vibration stops, sound ceases.
3
In a wave motion in string, every particle:MCQ
  • a) does not oscillate
  • b) does not displace at all
  • c) displaces from one end to the other end
  • d) oscillates
✓ Correct Answer: (d) oscillates
  1. Oscillation occurs perpendicular to the length or direction of energy transfer. Wave motion carries energy from one place to another without actually moving any matter.
4
What is the region called where the density of the medium increases above the average density due to a sound wave?MCQ
  • a) Rarefaction
  • b) Compression
  • c) Trough
  • d) Wavelength
✓ Correct Answer: (b) Compression
  1. In a compression region, the density of the medium increases above the average density.
5
When a pulse is sent through slinky/string, the physical quantity that travels along its length is:MCQ
  • a) speed
  • b) frequency
  • c) energy
  • d) wavelength
✓ Correct Answer: (c) energy
  1. A wave transfers energy. Energy travels through a wave along the length of the slinky or string.
6
Consider an astronaut outside the International Space Station (ISS) tapping two metal objects together. Another astronaut nearby, also outside the ISS, would not hear the clanking sound. Which principle explains this observation?MCQ
  • a) Sound waves are absorbed by space suits.
  • b) The inverse square law of sound intensity.
  • c) Sound transmission is affected by gravitational pull.
  • d) Sound needs a medium; space is vacuum.
✓ Correct Answer: (d) Sound needs a medium; space is vacuum.
  1. In outer space, there is a near vacuum, and thus sound cannot propagate. Hence, astronauts in spacesuits doing spacewalks cannot directly hear sounds like two metal objects clanking together.
7
S.I unit of sound waves wavelength is:MCQ
  • a) Metres
  • b) meters/second²
  • c) metres²
  • d) metres/second
✓ Correct Answer: (a) Metres
  1. Wavelength is the length between two consecutive peaks. The S.I unit of wavelength is Metres (m).
8
Why can astronauts in spacesuits not directly hear each other speak in outer space?MCQ
  • a) Helmets block sound.
  • b) Devices cancel noise.
  • c) Space is vacuum, no medium for sound.
  • d) Sounds are too faint.
✓ Correct Answer: (c) Space is vacuum, no medium for sound.
  1. In outer space, there is a near vacuum, and thus sound cannot propagate. Hence, astronauts in spacesuits doing spacewalks cannot directly hear each other speak.
9
During the propagation of a sound wave, what is actually moving forward across long distances?MCQ
  • a) Air particles move forward.
  • b) Medium moves as a whole.
  • c) Shape of source moves.
  • d) Disturbance (energy), not particles.
✓ Correct Answer: (d) Disturbance (energy), not particles.
  1. Only the wave disturbance and its energy travel long distances. The actual particles of the medium merely vibrate locally without migrating forward.
10
The distance between two consecutive compression of a sound wave is 5 cm. Then the wavelength of the wave is equal toMCQ
  • a) 20 cm
  • b) 10 cm
  • c) 5 cm
  • d) 2.5 cm
✓ Correct Answer: (c) 5 cm
  1. For a longitudinal wave (sound), the distance between two successive compressions equals one wavelength. Therefore, the wavelength is 5 cm.
11
Sound waves cannot propagate inMCQ
  • a) water
  • b) vacuum
  • c) air
  • d) metals
✓ Correct Answer: (b) vacuum
  1. Sound needs a material medium like solid, liquid, or gas to travel because the molecules carry sound waves. Sound cannot travel through vacuum since there are no molecules to vibrate and carry sound waves.
12
The diagram represents two different sound waves.
Wave X and Wave Y displacement graphs
Displacement-time graphs of Wave X and Wave Y
MCQ
  • a) The frequency and pitch of X is less than that of Y.
  • b) The frequency of X is less than Y but its pitch is same as Y.
  • c) The frequency and pitch of X is same as the frequency and pitch of Y.
  • d) The frequency of X is same as Y but its pitch is higher than Y.
✓ Correct Answer: (a) The frequency and pitch of X is less than that of Y.
  1. The frequency of wave X is lower than wave Y, hence its pitch is lower than wave Y too. The pitch of sound depends on the frequency.
13
In the bell jar experiment, as air is removedMCQ
  • a) elasticity falls
  • b) intensity falls
  • c) speed of sound falls
  • d) both intensity falls and speed of sound falls
✓ Correct Answer: (b) intensity falls
  1. As the air in the jar is pumped out, the sound becomes fainter, although the same current is passing through the bell. On reducing air pressure further, the intensity of sound reduces and stops.
14
Which body parts in humans assist in converting sound into speech or music?MCQ
  • a) Only the vocal cords.
  • b) The ears and brain.
  • c) The diaphragm and lungs.
  • d) Tongue, lips, mouth, nasal cavity.
✓ Correct Answer: (d) Tongue, lips, mouth, nasal cavity.
  1. Besides vocal cords, the tongue, lips, mouth, and nasal cavity in humans help in converting sound into speech or music.
15
On which of the following factor the speed of propagation of pulse in a slinky does not depend?MCQ
  • a) Length of slinky
  • b) Material of slinky
  • c) Dimensions of slinky
  • d) Room temperature
✓ Correct Answer: (c) Dimensions of slinky
  1. Dimensions include length, but only the area of the coil may be taken. The dimensions of the slinky do not affect the speed of propagation.
16
In the slinky analogy for sound propagation, what does the closeness or spreading out of the slinky's turns represent?MCQ
  • a) The frequency of the sound wave
  • b) The direction of wave propagation
  • c) The speed of sound
  • d) The higher or lower density of air
✓ Correct Answer: (d) The higher or lower density of air
  1. The closeness or spreading out of the slinky's turns represents regions of higher or lower density of air through which sound travels.
17
If you are in a location with no surrounding matter (a perfect vacuum), and a nearby explosion occurs, what would you perceive regarding the sound?MCQ
  • a) You would not hear any sound.
  • b) You would hear it after delay.
  • c) You would hear faint sound.
  • d) You would hear it normally.
✓ Correct Answer: (a) You would not hear any sound.
  1. Sound needs a medium to propagate. In a perfect vacuum, there is no medium, so no sound would be heard.
18
A bat can hear frequencies upto 120 kHz. Considering the speed of the sound to be 300 m/s, the wavelength of the signal isMCQ
  • a) 5 m
  • b) 1.25 m
  • c) 2.05 m
  • d) 0.25 cm
✓ Correct Answer: (d) 0.25 cm
  1. Frequency, ν = 120 kHz = 120 × 1000 Hz. Velocity v = 300 m/s.
  2. Wavelength λ = v/ν = 300/(120×1000) m = 300/(120×1000) × 100 cm = 0.25 cm.
19
What happens to the medium's particles when a sound wave propagates through it?MCQ
  • a) They remain stationary.
  • b) They vibrate about mean position.
  • c) They travel with the wave.
  • d) They move perpendicular to wave.
✓ Correct Answer: (b) They vibrate about mean position.
  1. The particles of the medium do not travel with the wave; they merely vibrate about their mean positions as the disturbance passes.
20
Light is a:MCQ
  • a) Longitudinal wave
  • b) Both
  • c) Transverse wave
  • d) None
✓ Correct Answer: (c) Transverse wave
  1. Light is a transverse wave because its components vibrate perpendicular to the direction of propagation.
21
The pitch of the two signals A and B shown below are PA and PB respectively. Then
Two pulse waves A and B
Two pulse waves A and B
MCQ
  • a) PA = PB
  • b) PA = 2PB
  • c) PA < PB
  • d) PA > PB
✓ Correct Answer: (d) PA > PB
  1. The sensation of frequency is commonly referred to as the pitch of a sound. A high-pitch sound corresponds to a high-frequency sound wave and a low-pitch sound corresponds to a low-frequency sound wave. Signal A has a higher frequency than B.
22
When a pulse produced in a string moves through it and strikes a rigid pole, it is reflected back and the space of the reflected pulse resembles the shape given is
Four reflected pulse shapes
Four possible reflected pulse shapes (i, ii, iii, iv)
MCQ
  • a) (iv)
  • b) (iii)
  • c) (ii)
  • d) (i)
✓ Correct Answer: (c) (ii)
  1. When a pulse strikes a rigid pole and reflects back, its shape inverts. Reflection brings a reaction to the action of a wave, resulting in the shape shown in (ii).
23
In the curve figure, half the wavelength is
Sine curve with points A B C D E
Sine curve with points A, B, C, D, E marked
MCQ
  • a) B D
  • b) A E
  • c) A B
  • d) D E
✓ Correct Answer: (a) B D
  1. As one wavelength = one crest + one trough, half the wavelength = one crest or one trough = AC (or CE).
  2. Further, AC = AB + BC = BC + CD = BD (as AB = CD). So half the wavelength = BD.
24
Match the following with correct response.
(1) Audible range?
(2) Infrasonic?
(3) Ultrasonic?
(4) Supersonic?
Options: (A) Less than 20 Hz   (B) Speed greater than sound in air   (C) More than 20,000 Hz   (D) 20 Hz to 20,000 Hz
MCQ
  • a) 1-D, 2-A, 3-C, 4-B
  • b) 1-B, 2-D, 3-A, 4-C
  • c) 1-C, 2-B, 3-D, 4-A
  • d) 1-A, 2-C, 3-B, 4-D
✓ Correct Answer: (a) 1-D, 2-A, 3-C, 4-B
  1. Sound whose frequency lies between 20 Hz and 20,000 Hz which we can hear is called audible sound.
  2. Inaudible sounds with frequency less than 20 Hz are infrasonic. Inaudible sounds with frequency more than 20,000 Hz are ultrasonic. A body travelling faster than sound is travelling at supersonic speed.
25
Match the following with the correct response:
(a) A moving disturbance?
(b) Propagation requires a material medium?
(c) Particles vibrate perpendicular to the direction of wave propagation?
(d) Back and forth motion?
Options: (i) Mechanical waves   (ii) Oscillatory motion   (iii) Transverse waves   (iv) Wave
MCQ
  • a) (a)-(iii), (b)-(ii), (c)-(iv), (d)-(i)
  • b) (a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)
  • c) (a)-(iv), (b)-(i), (c)-(iii), (d)-(ii)
  • d) (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)
✓ Correct Answer: (c) (a)-(iv), (b)-(i), (c)-(iii), (d)-(ii)
  1. A wave is a moving disturbance. Mechanical waves require a material medium for propagation, since they rely on particle interaction and cannot travel through a vacuum.
  2. A transverse wave has oscillations perpendicular to the direction of energy transfer. A wave in which particles oscillate back and forth in the same direction as wave motion is called a longitudinal (oscillatory) wave.
26
Match the following with correct response.
(1) Speed of sound in Aluminium?
(2) Speed of sound in water?
(3) Speed of sound in air?
(4) Speed of sound in oxygen gas?
Options: (A) 6420 ms⁻¹   (B) 343 ms⁻¹   (C) 1484 ms⁻¹   (D) 326 ms⁻¹
MCQ
  • a) 1-B, 2-D, 3-A, 4-C
  • b) 1-D, 2-A, 3-C, 4-B
  • c) 1-C, 2-B, 3-D, 4-A
  • d) 1-A, 2-C, 3-B, 4-D
✓ Correct Answer: (d) 1-A, 2-C, 3-B, 4-D
  1. The speed of sound is different in different media: Aluminium = 6420 ms−1, Water = 1484 ms−1.
  2. Air = 343 ms−1, Oxygen gas = 326 ms−1.
27
Wave motion is a periodic ________ produced by a vibrating body.MCQ
  • a) Momentum
  • b) Disturbance
  • c) oscillations
  • d) Energy
✓ Correct Answer: (b) Disturbance
  1. Wave motion is a periodic disturbance in the medium produced by a vibrating body. This disturbance moves into the medium to produce sounds; wave motion is also known as the propagation of disturbances.
28
Statement A: An object moving at a speed greater than that of a sound is moving at ultrasonic speed.
Statement B: In wave motion, only energy is transferred.
Which of the two statements is true?MCQ
  • a) Both A and B
  • b) Statement A
  • c) Neither A or B
  • d) Statement B
✓ Correct Answer: (d) Statement B
  1. An object moving faster than sound is moving at supersonic speed, not ultrasonic. So Statement A is false. Wave motion transfers energy from one point to another, displacing particles with little or no associated mass transport — Statement B is true.
29
Find the incorrect statement
A. Sound waves are electromagnetic waves.
B. You can't talk on moon.
C. Speed of sound is different at different temp.
D. Shock waves are used to break up kidney stone and gall stones without surgery.MCQ
  • a) D
  • b) C
  • c) A
  • d) B
✓ Correct Answer: (c) A
  1. Sound waves are longitudinal mechanical waves (not electromagnetic) that require a material medium for propagation. The moon has no atmosphere, so sound cannot travel there. The speed of sound differs with temperature, and ultrasound shock waves are indeed used to break up kidney stones.
30
Find the incorrect statement.
A. The speed of the wave doesn't depend on properties of the medium.
B. Ultrasound is produced by electronic oscillator.
C. 120 dB means intensity is 1 W/m².
D. The distance between crest and trough is λ/2.MCQ
  • a) (C)
  • b) (D)
  • c) (B)
  • d) (A)
✓ Correct Answer: (d) (A)
  1. The speed of a sound wave depends on the properties of the medium through which it moves, and the only way to change the speed is to change the properties of the medium. So statement A is incorrect.
31
Which of the following is incorrect-
A. SI Unit of frequency is hertz
B. SI Unit of wavelength is ms−1
C. SI Unit of velocity is ms−2
D. SI unit of time period is secMCQ
  • a) A and B are incorrect
  • b) A, B and C are incorrect
  • c) B and C are incorrect
  • d) All of these
✓ Correct Answer: (c) B and C are incorrect
  1. SI unit of wavelength is the metre (m), not ms−1. SI unit of velocity is ms−1, not ms−2. So B and C are incorrect.
32
A pulse was created in a slinky/string of length 4 m by a group of students. They observed that it returned, after reflection, at the point of creation 6 times in 10 seconds and calculated the speed as follows:
StudentsABCD
Speed m/s0.42.44.89.6
The correct speed was calculated by the student:MCQ
  • a) A
  • b) B
  • c) C
  • d) D
✓ Correct Answer: (c) C
  1. Total distance travelled = 6 reflections × 2 × 4 m (to and fro) = 48 m. But per single "trip" calculation: distance = 8 m per round trip.
  2. Time taken t = 10/6 s. Speed = Distance/Time = 8 ÷ (10/6) = 8 × 6/10 = 4.8 m/s.
33
The correct statement in the following is:
A. Sound waves are longitudinal and light waves are transverse
B. Sound waves and light waves are both longitudinal waves
C. Sound waves are transverse and light waves are longitudinal
D. Both sound waves and light waves are transverseMCQ
  • a) (A)
  • b) (C)
  • c) (D)
  • d) (B)
✓ Correct Answer: (a) (A)
  1. Sound waves are mechanical and elasticity-based, hence longitudinal. Light waves are electromagnetic and are transverse.
34
Which of the following statement is true?
A. The frequency of man's voice more than that of woman's voice.
B. Repeated claps of thunder in quick succession are called rolling of thunder.
C. Timbre is a typical feature of a sound which enables us to distinguish between the sounds of same loudness and pitch.MCQ
  • a) Both statement (B) and (C)
  • b) Only statement (B)
  • c) Only statement (C)
  • d) Only statement (A)
✓ Correct Answer: (a) Both statement (B) and (C)
  1. Rolling thunder is repeated claps of thunder in quick succession. Timbre allows us to distinguish between sounds of the same loudness and pitch. Statement A is incorrect — a woman's voice has a higher frequency (speaks about an octave higher) than a man's.
35
Assertion (A): Sound is produced when an object vibrates or moves back and forth rapidly.
Reason (R): The energy required to make an object vibrate is provided by some outside source.Assertion-Reason
  • a) Both A and R are true and R is the correct explanation of A.
  • b) Both A and R are true but R is not the correct explanation of A.
  • c) A is true but R is false.
  • d) A is false but R is true.
✓ Correct Answer: (b) Both A and R are true but R is not the correct explanation of A.
  1. When a vibrating object moves forward, it compresses air, creating regions of high pressure. As it moves back and forth, compressions and rarefactions form a sound wave — this is true. The energy for vibration comes from an outside source like our hand or wind — also true, but this fact doesn't directly explain why vibration produces sound.
36
Assertion (A): Supersonic speed exceeds the speed of sound.
Reason (R): Bullets, jet aircraft, etc. often travel at supersonic speeds.Assertion-Reason
  • a) Both A and R are true and R is the correct explanation of A.
  • b) Both A and R are true but R is not the correct explanation of A.
  • c) A is true but R is false.
  • d) A is false but R is true.
✓ Correct Answer: (b) Both A and R are true but R is not the correct explanation of A.
  1. When the speed of any object exceeds the speed of sound, it is said to be travelling at supersonic speed — true. Bullets, jet aircraft, etc. often travel at supersonic speeds — also true, but R is a separate fact/example rather than an explanation of the definition in A.
37
Assertion (A): Sound would travel faster on a hot summer day than on a cold winter day.
Reason (R): Velocity of sound is directly proportional to the square of its absolute temperature.Assertion-Reason
  • a) Both A and R are true and R is the correct explanation of A.
  • b) Both A and R are true but R is not the correct explanation of A.
  • c) A is true but R is false.
  • d) A is false but R is true.
✓ Correct Answer: (c) A is true but R is false.
  1. Sound does travel faster on a hot day than a cold day — true. However, the velocity of sound is directly proportional to the square root of absolute temperature, not the square — so R is false.
38
Assertion (A): The quality of sound enables us to distinguish one sound from another having the same pitch and loudness.
Reason (R): The sound which is more pleasant is said to be of a low quality.Assertion-Reason
  • a) Both A and R are true and R is the correct explanation of A.
  • b) Both A and R are true but R is not the correct explanation of A.
  • c) A is true but R is false.
  • d) A is false but R is true.
✓ Correct Answer: (c) A is true but R is false.
  1. The quality or timbre of a sound does enable us to distinguish one sound from another having the same pitch and loudness — true. However, a sound which is more pleasant is said to be of rich/high quality, not low quality — so R is false.

Section B · Short Answer Questions (Q39–Q54)

2 Marks each
39
Match the following Column A with Column B:
(a) Amplitude?
(b) Frequency?
(c) Wavelength?
(d) Time period?
Options: (i) The number of complete oscillations per second   (ii) The magnitude of maximum disturbance in the medium on either side of the mean position   (iii) The time taken for one complete oscillation in the density (or pressure) of the medium   (iv) The distance between two consecutive compressions or two consecutive rarefactions
✓ (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
40
Match the following Column A with Column B:
(a) The portion of the medium where density has a value smaller than its average value?
(b) A region of rarefied air?
(c) The number of complete oscillations per second?
(d) The portion of the medium where density has a value larger than its average value?
Options: (i) Crest   (ii) Frequency   (iii) Trough   (iv) Rarefaction
✓ (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)
41
Match the following Column A with Column B:
(a) Wavelength?
(b) Amplitude?
(c) Time period?
(d) Compression?
Options: (i) A   (ii) λ   (iii) C   (iv) T
✓ (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
42
Fill in the blanks:
  • ________ is the most common medium through which sound travels.
  • The disturbance which moves through a medium when the particles of the medium set the neighboring particles into motion is known as a ________.
  1. (a) Air
  2. (b) Wave
43
How does the graphical representation of density versus distance illustrate the alternating regions of compression and rarefaction in a propagating sound wave?
  1. In a graph plotting density against distance, regions where the curve rises above the average density line indicate compressions. The highest point on this rise is the crest, signifying maximum density.
  2. Conversely, sections where the curve falls below the average density line represent rarefactions, with the lowest point (the trough) indicating minimum density.
  3. This visual representation clearly shows the periodic fluctuation and spatial distribution of these regions.
44
Two astronauts are repairing the arm of a space station together during a spacewalk. Can they talk to each other and hear the sounds of metal clanking as they do on the Earth?
  1. No, the astronauts cannot talk to each other directly in space or hear the sound of metal clanking.
  2. Sound needs a material medium (like air, water, or solids) to travel. In space, there is no atmosphere (vacuum), so sound waves cannot propagate. Therefore, even though they may speak or the metal may collide, the sound cannot reach the other astronaut.
45
How are the wavelength and frequency of a sound wave related to its speed?
v = ν × λ
  1. Where v = velocity/speed of the wave, ν = frequency of the wave, and λ = wavelength of the wave.
46
Prove that V = υλ, where the symbols have their usual meanings.
  1. Let the time period of a wave be T seconds. In T seconds, the number of waves generated = 1.
  2. So, in 1 second, the number of waves generated = 1/T. But the number of waves generated in 1 second is frequency. Therefore, υ = 1/T.
  3. Now, Velocity = Distance travelled / Time taken = λ/T = (1/T) × λ = υ × λ.
✓ V = υλ (proved)
47
Describe with the help of a diagram, how compressions and rarefactions are produced in air near a source of sound.
  1. Sound waves are propagated because of compressions and rarefactions in the particles of the medium.
  2. The region where particles come closer together is called compression, and the region where particles move farther apart from each other is called rarefaction. As the source vibrates back and forth, it alternately pushes air particles together (compression) and pulls them apart (rarefaction), and this pattern travels outward as a sound wave.
48
Define :-
  • Time Period
  • Amplitude of a wave
  1. (a) Time Period (T): The time required by a wave to complete one vibration is called the time period.
  2. (b) Amplitude (A): The magnitude of the maximum disturbance in the medium on either side of the mean value is called the amplitude of a wave.
49
What is a 'vacuum' and how does it affect the transmission of sound?
  1. A vacuum is a space devoid of matter, meaning it contains no medium.
  2. Sound cannot be transmitted through a vacuum because it requires a material medium (like solids, liquids, or gases) to propagate. The absence of particles in a vacuum prevents the vibrations of sound waves from being carried forward.
50
Describe the primary characteristic of particle movement in a longitudinal wave.
  1. In a longitudinal wave, the particles of the medium oscillate back and forth. This vibration occurs parallel to the direction in which the wave itself is propagating.
  2. This consistent motion allows the disturbance to travel through the medium without the individual particles undergoing significant displacement from their mean positions, transmitting energy efficiently.
51
Cite an experiment to show that sound needs a material medium for its propagation.
  1. Take an electric bell and an airtight glass bell jar. The electric bell is suspended inside the airtight bell jar, which is connected to a vacuum pump.
  2. If you press the switch, you will be able to hear the bell. Now start the vacuum pump. As the air in the jar is pumped out gradually, the sound becomes fainter, although the same current is passing through the bell.
  3. After some time, when less air is left inside the bell jar, you will hear a very feeble sound. If we evacuate the bell jar completely, no sound is heard.
✓ Result: This activity shows that sound needs a medium to propagate
52
A longitudinal wave of wavelength 1 cm travels in air with a speed of 330 m/s. Calculate the frequency of the wave. Can this wave be heard by a normal human?
v = υλ ⇒ υ = v/λ
  1. Given: λ = 1 cm = 1×10−2 m, v = 330 m/s.
  2. Frequency, υ = 330/(1×10−2) = 33,000 Hz.
  3. This frequency is more than 20,000 Hz (maximum frequency audible to man). Hence, it cannot be heard by a normal human being.
53
The frequency of a source of sound is 100 Hz. How many times does it vibrate in a minute?
  1. Frequency of the source = 100 Hz means the sound source vibrates 100 times in one second.
  2. Therefore, vibrations made in 1 minute (60 sec) = 100 × 60 = 6000 times.
54
A sound wave has a frequency of 2 kHz and wave length 35 cm. How long will it take to travel 1.5 km?
  1. Given: Frequency, υ = 2 kHz = 2000 Hz. Wavelength, λ = 35 cm = 0.35 m.
  2. Speed, v = λυ = 0.35 × 2000 = 700 m/s.
  3. Time taken to travel distance d = 1.5 km = 1500 m: t = d/v = 1500/700 = 15/7 ≈ 2.1 s.
✓ Sound takes 2.1 s to travel 1.5 km

Section C · Short Answer Questions – II (Q55–Q61)

3 Marks each
55
State whether the given statement is True or False:
  • The change in density (or pressure) from the maximum value to the minimum value and again to the maximum value is called amplitude.
  • Sound propagates in the medium as a series of compressions and rarefactions.
  • The time taken for one complete oscillation in the density (or pressure) of the medium is called the time period (T) of the wave.
  1. (a) False. The change in density (or pressure) from the maximum value to the minimum value and again to the maximum value is called an oscillation, not amplitude.
  2. (b) True.
  3. (c) True.
56
Fill in the blanks:
  • ________ is determined by the wave form of the sound.
  • The speed of sound ________ with the increase in temperature.
  • The distance between two consecutive compressions or two consecutive rarefactions is called ________ of the wave.
  1. (a) Quality (Timbre)
  2. (b) Increases
  3. (c) Wavelength
57
Observe the given figure and answer the following questions:
Wave A and Wave B graphs
Wave A and Wave B graphs showing Amplitude and Wavelength, both with Velocity = 325 m/s and Frequency: 440 Hz
  • Identify the characteristics of the two graphs as shown above in the given figure.
  • What is the relationship between the velocity of sound, its wavelength, and frequency?
  • What is the term for the magnitude of the maximum disturbance in the medium on either side of the mean value?
  • Give the unit of frequency?
  1. (i) In the graphical figure, both waves are of the same frequency but with different amplitude. In Wave A, amplitude is less, and in Wave B, amplitude is higher.
  2. (ii) The relationship between velocity of sound, wavelength, and frequency is: Velocity of sound = frequency × wavelength.
  3. (iii) The term is Amplitude.
  4. (iv) The unit of frequency is hertz (Hz).
58
Graphs representing two sound waves are given in the figure. If the scales on the X and Y axes of the two graphs are the same, which of the two sound waves has (i) greater wavelength, and (ii) smaller amplitude?
Density distance graphs a and b
Two density-distance graphs (a) and (b)
(i) Greater Wavelength
  1. Wave (a) has the greater wavelength.
  2. Reasoning: Wavelength (λ) is the horizontal distance between two consecutive peaks (crests) or troughs. Looking at the X-axis, the distance between peaks in graph (a) is significantly larger than in graph (b). Since the scales are the same, a longer physical distance represents a greater wavelength.
(ii) Smaller Amplitude
  1. Wave (a) has the smaller amplitude.
  2. Reasoning: Amplitude is the maximum vertical displacement of the wave from its central equilibrium position (X-axis). The height of the peaks in wave (a) is much shorter compared to wave (b). Therefore, wave (a) represents a softer sound with smaller amplitude, while wave (b) represents a louder sound with greater amplitude.
59
Kunal and Abhimanyu were waiting to go across a railway crossing. Kunal jumped over the barrier and curiously put his ear on the railway track. Abhimanyu opposed Kunal and pulled him away from the railway track.
  • Why did Kunal put his ear on the railway track?
  • Can sound travel faster through (i) copper (ii) water?
  • Why did Abhimanyu pull Kunal away from the railway track?
  1. (a) To hear the sound of the coming train because sound travels within the rail track and helps get an idea of the distance of an incoming train.
  2. (b) Sound travels faster through copper (solid) than water (liquid), since sound generally travels fastest in solids, then liquids, then gases.
  3. (c) For safety, as he cared for his friend and wanted to prevent an accident from an approaching train.
60
Describe the construction and typical application of a tuning fork in the context of sound experiments.
  1. A tuning fork is a U-shaped instrument, typically constructed from steel or aluminum, featuring a stem and two parallel sides called prongs or tines.
  2. Its primary application in sound experiments involves striking these tines on a resilient surface, causing them to vibrate at a specific frequency.
  3. This vibration produces a pure tone, making it invaluable for demonstrating the relationship between vibration and sound, and for precise pitch reference or calibration in various scientific and musical contexts.
61
Explain the fundamental principle behind sound production, providing examples of different vibrating components involved in musical instruments.
  1. The fundamental principle of sound production is the vibration of an object. When an object undergoes periodic to-and-fro motion, it displaces the surrounding medium, creating sound waves.
  2. In musical instruments, various components vibrate to produce sound. Examples include vibrating strings in guitars, vibrating membranes in drums, and vibrating air columns in flutes or trumpets.
  3. Often, multiple vibrating parts interact to create complex sounds, with the primary vibrating object being the source.

Section D · Case Study Based Questions (Q62–Q64)

4 Marks each
62
Case Study: Srishti learned that bats are nocturnal animals capable of flying and hunting in complete darkness without crashing into obstacles. They produce short bursts of ultrasonic waves (sound waves having frequency above 20,000 Hz or 20 kHz) and listen to the echoes reflected from nearby objects. By interpreting these echoes, bats determine the position and distance of obstacles or prey. This ability is known as echolocation.
Humans have developed a similar technology called SONAR (Sound Navigation And Ranging), which uses ultrasonic waves to detect objects underwater, measure ocean depth, and locate submerged objects like shipwrecks. Sound waves with frequencies below 20 Hz are called infrasonic waves and are used in studying natural phenomena such as earthquakes and volcanic activities.
  • Name any two animals other than bats that use echolocation for navigation or hunting. (1)
  • State one application of ultrasonic waves in science or medicine (excluding SONAR). (1)
  • Humans cannot hear ultrasonic or infrasonic waves. Name one animal that can detect: (i) ultrasonic waves (ii) infrasonic waves (2)
    OR — A dog whistle emits sound of frequency 25 kHz. Can a human hear it? Can a dog hear it? Give reasons based on the audible frequency range of humans and dogs. (2)
  1. (i) Dolphins, Whales use echolocation for navigation or hunting.
  2. (ii) Ultrasonic waves are used in medical ultrasonography (ultrasound scanning) for imaging internal organs.
  3. (iii)(i) Ultrasonic waves → Dog / Bat / Cat (any one). (ii) Infrasonic waves → Elephant / Whale (any one).
OR
  1. Humans: Cannot hear it, because the human audible range is approximately 20 Hz to 20,000 Hz, and 25 kHz exceeds this range.
  2. Dogs: Can hear it, because dogs can detect ultrasonic frequencies above 20 kHz, including 25 kHz.
✓ (i) Dolphins, Whales   (ii) Medical ultrasonography   (iii) Dog/Bat (ultrasonic), Elephant/Whale (infrasonic)
63
Case Study: During a thunderstorm, Govind observed that he always saw the flash of lightning before hearing the sound of thunder, even though both events occurred at the same time. His teacher explained that light travels much faster than sound. The speed of sound in dry air is approximately 331 m s−1 at 0°C and about 344 m s−1 at 22°C, indicating that the speed of sound increases with temperature. Sound travels nearly 4-5 times faster in water and 15-20 times faster in solids than in air. The speed (v), frequency (ν), and wavelength (λ) of a sound wave are related by the equation: v = λν
By measuring the time interval between the flash of lightning and the sound of thunder, the distance of the lightning strike from the observer can be estimated.
  • Define the term wavelength of a sound wave. State its SI unit. (1)
  • Explain how the speed of sound in air changes with temperature. Support your answer using the values given in the passage. (1)
  • A sound wave is travelling through air. If its frequency is doubled, what will happen to its wavelength and time period? Justify your answer using the relation v = λν. (2)
    OR — A sound wave has a frequency of 680 Hz and travels through air at a speed of 340 m s−1. Calculate: its wavelength, and its time period. (2)
  1. (i) Wavelength is the distance between two consecutive compressions or two consecutive rarefactions in a sound wave. SI Unit: metre (m).
  2. (ii) The speed of sound in air increases with temperature. According to the passage, the speed of sound is about 331 m s−1 at 0°C and 344 m s−1 at 22°C. Thus, a rise in temperature increases the speed of sound.
  3. (iii) For a given medium, the speed of sound v remains constant. Using v = λν: If frequency (ν) is doubled, the wavelength (λ) must become half to keep v constant. Also, T = 1/ν, so when frequency is doubled, time period becomes half.
✓ Wavelength = Half of original value; Time period = Half of original value
OR
  1. Given: v = 340 m s−1, ν = 680 Hz.
  2. Wavelength: λ = v/ν = 340/680 = 0.5 m.
  3. Time Period: T = 1/ν = 1/680 ≈ 0.00147 s (≈ 1.47 × 10−3 s).
64
Case Study: Sound is produced due to vibrations, which are periodic to-and-fro motions of an object. When an object vibrates, it disturbs the surrounding medium and generates sound waves. Everyday examples include plucking a string, striking a metal object, or blowing air into a flute, all of which create vibrations that produce sound. Musical instruments rely on vibrating parts such as strings, membranes, or air columns to generate sound. In many instruments, multiple vibrating components work together to produce rich tones. The object responsible for producing sound is called the source of sound.
Examples of vibrating sources infographic
"Examples of Vibrating Sources" infographic — plucked strings, vocal cords, air columns, drum membranes, nature & animals, scientific study of vibration, and musical tones
Even animals produce sound through vibrations; for instance, grasshoppers and crickets create sound by rubbing their body parts. A common scientific instrument used to study sound is the tuning fork, a U-shaped metal bar that vibrates when struck. These vibrations demonstrate that sound cannot exist without motion, highlighting vibration as the fundamental cause of sound production.
  • What is the main cause of sound production? (1)
  • What is a source of sound? (1)
  • How do musical instruments produce sound? (2)
    OR — Explain how a tuning fork produces sound. (2)
  1. (i) The main cause of sound production is vibration. When an object vibrates, it creates disturbances in the surrounding medium, which travel as sound waves and are heard as sound.
  2. (ii) A source of sound is any vibrating object that produces sound. Examples include musical instruments, vibrating strings, or objects like tuning forks that generate sound through motion.
  3. (iii) Musical instruments produce sound through vibrations of strings, membranes, or air columns. These vibrations create sound waves, and in many instruments, multiple vibrating parts combine to produce complex and rich sounds.
OR
  1. A tuning fork produces sound when its prongs are struck, causing them to vibrate. These vibrations disturb the surrounding air, creating sound waves that travel to our ears and are heard as sound.
✓ (i) Vibration   (ii) Any vibrating object   (iii) Vibrating strings/membranes/air columns

Section E · Long Answer Questions (Q65–Q69)

5 Marks each
65
  • What is meant by frequency of sound waves?
  • Give the range of frequencies of sound waves that an average human ear can detect.
  • A source of wave produces 20 crests and 20 troughs in 0.2 s. The distance between a crest and next trough is 50 cm. Find the a. wavelength, b. frequency, c. time period of the wave.
  1. (i) The number of waves produced per second is called the frequency of the wave.
  2. (ii) Sound waves audible to an average human ear range from 20 Hz to 20 kHz.
(iii) Calculations
  1. a. Wavelength: The distance between a crest and next trough is λ/2. Given λ/2 = 50 cm, so λ = 100 cm or 1 m.
  2. b. Frequency: One vibration (oscillation) consists of one trough and one crest. In 0.2 s, number of vibrations = 20. So, in 1 s, number of vibrations = 20/0.2 = 100. Frequency = 100 Hz.
  3. c. Time period: T = 1/frequency = 1/100 = 0.01 sec.
66
Draw a curve showing density or pressure variations with respect to distance for a disturbance produced by sound. Mark the position of compression and rarefaction on this curve. Also, define wavelengths and time period using this curve.
  1. A curve showing density (or pressure) versus distance is a sine-shaped wave, where the crests represent regions of compression (maximum density) and the troughs represent regions of rarefaction (minimum density).
Wavelength
  1. Wavelength is the distance between two consecutive compressions or two consecutive rarefactions of a sound wave. Wavelength is represented by the Greek letter λ (lambda). The SI unit of wavelength is metre (m).
Time period
  1. Time period is the time taken to travel the distance between any two consecutive compression or rarefaction from a fixed point. The time period of a sound wave is represented by the letter 'T'. The SI unit of time period is second (s).
67
Represent graphically by two separate diagrams in each case
  • Two sound waves having the same amplitude but different frequencies?
  • Two sound waves having the same frequency but different amplitudes.
  • Two sound waves having different amplitudes and also different wavelengths.
(i) Same amplitude, different frequency
Two waves same amplitude different frequency
Two waves with same amplitude but different frequency
(ii) Same frequency, different amplitude
Two waves same frequency different amplitude
Two waves with same frequency but different amplitude
(iii) Different amplitudes and different wavelengths
Two waves different amplitude and wavelength
Two waves with different amplitudes and different wavelengths
68
  • Which characteristic of sound helps to identify your friend by his voice while sitting with others in a dark room?
  • State the relationship between frequency and time period of a wave. The wavelength of vibrations produced on the surface of the water is 4 cm. If the wave velocity is 20 m/s find the frequency and Time period.
  1. (i) Timbre or quality of sound, which is distinct from its pitch and intensity, helps to identify your friend by his voice while sitting with others in a dark room.
(ii) Relationship and Calculation
Frequency = 1/Time Period
  1. Given: λ = 4 cm = 0.04 m, v = 20 m/s. Find frequency (ν) and time period (T).
  2. ν = v/λ = 20/0.04 = 500 Hz.
  3. T = 1/ν = 1/500 = 0.002 s.
69
  • Sound is produced when your school bell is struck with a hammer. Why?
  • A powerful sound signal sent from a ship is received again after 4.8 seconds. How deep is the ocean bottom? (Speed of sound in water = 1500 m/s).
  1. (i) Sound is produced when a material body is made to vibrate with some mechanical energy. So, the school bell is struck with a hammer to make it vibrate, and thus the sound is produced.
(ii) Depth calculation
  1. Time taken by the signal to reach the bottom and come back = 4.8 s. Speed of sound in water = 1500 m/s.
  2. Depth of ocean, h = (v × t)/2 = (1500 × 4.8)/2 = 1500 × 2.4.
  3. h = 3600 m.
✓ Depth of the ocean = 3600 m
Prepared by Sumeet Sahu · Mob: 8103405051 · Unique Study Point
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๐Ÿ“‹ Details

ClassClass IX (CBSE / NCERT)
SubjectScience
ChapterChapter 10: Sound Waves: Characteristics and Applications
Resource TypeWorksheet
Last Updated11 September 2026
Session2026-27 (Latest NCERT Syllabus)
Downloads10+
Prepared bySumeet Sahu, Unique Study Point, Indore
CostFree
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