Class IXMaths📋 Sample PaperCh 12: QuadrilateralsNCERT book: Ganita Manjari
Updated 22 Oct 2026
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Class 9 Maths Ganita Manjari Chapter 12: Quadrilaterals – Test Paper with Solutions
Part II • CBSE 2026-27 • 40 Marks • 60 Minutes
18 QuestionsStep-by-step solutionsFree
This free practice test paper with solutions for Class 9 Maths Chapter 12, Quadrilaterals (NCERT Ganita Manjari, Part II, session 2026-27) has 18 questions for 40 marks and is made to be finished in about 60 minutes. The paper has MCQs, short answer questions, a case study and long answer questions. Try every question on your own first. Then tap Show Answer to see the full working, with the marks for each step, and compare it with your own solution.
What this test paper covers
Quadrilaterals: angle sum, naming and convex quadrilaterals
Parallelograms: properties and the tests that prove a quadrilateral is a parallelogram
Midpoint Theorem: the theorem and its converse
Medians and the centroid, and the Varignon parallelogram
Tiling the plane: why the angles at a vertex must add up to 360 degrees
How the paper is arranged
Section
Type of questions
Questions
Marks each
Total
A
Multiple choice questions
8
1
8
B
Short answer questions
3
2
6
C
Short answer questions
4
3
12
D
Case study
1
4
4
E
Long answer questions
2
5
10
Total
18
40
Try each question first, then tap Show Answer to check your working.
SECTION AMultiple Choice Questions (1 mark each)8 marks
1
The angles of a quadrilateral are 95°, 85°, 110° and x°. The value of x is:
1 mark
A60
B65
C70
D80
Answer and working
The angles of a quadrilateral add up to 360°, so x = 360 − (95 + 85 + 110) = 360 − 290 = 70.
Answer: (C) 70
2
Two adjacent angles of a parallelogram are in the ratio 4 : 5. The smaller angle is:
1 mark
A70°
B80°
C90°
D100°
Answer and working
Adjacent angles of a parallelogram add up to 180°. 4 + 5 = 9 parts, so one part is 180 ÷ 9 = 20°. The smaller angle is 4 × 20 = 80°.
Answer: (B) 80°
3
The diagonals of parallelogram PQRS meet at O. If QS = 26 cm, then OQ is:
1 mark
A13 cm
B26 cm
C52 cm
D6.5 cm
Answer and working
The diagonals of a parallelogram bisect each other, so OQ = 12 × 26 = 13 cm.
Answer: (A) 13 cm
4
Which of these is NOT enough to prove that a quadrilateral is a parallelogram?
1 mark
Aboth pairs of opposite sides are equal
Bthe diagonals bisect each other
Cone pair of opposite sides is equal and parallel
Done pair of opposite sides is parallel
Answer and working
One pair of parallel sides gives only a trapezium. The pair must also be equal. The other three are tests for a parallelogram.
Answer: (D) one pair of opposite sides is parallel
5
D and E are the midpoints of the sides AB and AC of triangle ABC. If DE = 9 cm, then BC is:
1 mark
A4.5 cm
B18 cm
C27 cm
D9 cm
Answer and working
By the Midpoint Theorem, DE = 12 BC, so BC = 2 × 9 = 18 cm.
Answer: (B) 18 cm
6
The centroid G of triangle ABC lies on the median BE, and BG = 10 cm. Then GE is:
1 mark
A10 cm
B20 cm
C5 cm
D15 cm
Answer and working
The centroid divides a median 2 : 1 from the vertex, so BG = 2 × GE and GE = 10 ÷ 2 = 5 cm.
Answer: (C) 5 cm
7
The midpoints of the sides of a quadrilateral whose diagonals are equal and perpendicular form a:
1 mark
Arectangle
Brhombus
Ctrapezium
Dsquare
Answer and working
Equal diagonals make the midpoint figure a rhombus, perpendicular diagonals make it a rectangle, and both together make it a square.
Answer: (D) square
8
The plane can be tiled with copies of any quadrilateral because:
1 mark
Aits four angles add up to 360°
Ball its sides are equal
Cits diagonals are equal
Dits opposite sides are parallel
Answer and working
The four angles of any quadrilateral add up to 360°, so four copies can fit around a point with no gap and no overlap.
Answer: (A) its four angles add up to 360°
SECTION BShort Answer Questions (2 marks each)6 marks
9
The angles of a quadrilateral are (x + 20)°, (2x − 10)°, (x + 50)° and 2x°. Find x and the four angles.
6x = 300, so x = 50. The angles are 70°, 90°, 100° and 100° (sum = 360°).
1 mark
Answer: x = 50; angles 70°, 90°, 100°, 100°
10
The diagonals of parallelogram ABCD meet at O. AO = (3x − 2) cm and OC = (x + 8) cm. Find x and the length of AC.
2 marks
Answer and working
The diagonals of a parallelogram bisect each other, so AO = OC: 3x − 2 = x + 8.
1 mark
2x = 10, so x = 5. AO = 13 cm, so AC = 2 × 13 = 26 cm.
1 mark
Answer: x = 5; AC = 26 cm
11
The quadrilateral ABCD can also be named BCDA. (a) Write two other names for it. (b) Why can it not be named ACBD?
2 marks
Answer and working
(a) Any two of: CDAB, DABC, DCBA, ADCB, BADC, CBAD.
1 mark
(b) The letters must go round the figure, so that neighbouring letters are neighbouring vertices. In ACBD the first two letters A and C are not the ends of a side (AC is a diagonal).
1 mark
Answer: (a) for example CDAB and DCBA (b) the letters must go round the figure
SECTION CShort Answer Questions (3 marks each)12 marks
12
Three angles of a quadrilateral are 75°, 105° and 95°.
3 marks
(a)Find the fourth angle.[2]
(b)Is the quadrilateral convex? Give a reason.[1]
Answer and working
(a) The angles add up to 360°, so the fourth angle = 360 − (75 + 105 + 95) = 360 − 275 = 85°.
2 marks
(b) Yes, it is convex, because all four angles (75°, 105°, 95° and 85°) are less than 180°.
1 mark
Answer: (a) 85° (b) convex
13
In parallelogram ABCD, the bisector of ∠A meets the side DC at E. Show that DE = DA.
3 marks
Answer and working
AB ∥ DC and AE is a transversal, so ∠EAB = ∠AED (alternate angles).
1 mark
AE bisects ∠A, so ∠DAE = ∠EAB.
1 mark
Hence ∠DAE = ∠AED. In triangle ADE, equal angles have equal sides opposite them, so DE = DA.
1 mark
Answer: DE = DA (proved)
14
In triangle ABC, M is the midpoint of AB. The line through M parallel to BC meets AC at N. If BC = 11 cm and AC = 14 cm, find MN and AN. Name the theorems you use.
3 marks
Answer and working
MN ∥ BC and M is the midpoint of AB, so by the converse of the Midpoint Theorem N is the midpoint of AC.
1 mark
AN = 12 × 14 = 7 cm.
1 mark
By the Midpoint Theorem, MN = 12 × BC = 12 × 11 = 5.5 cm.
1 mark
Answer: MN = 5.5 cm; AN = 7 cm
15
In quadrilateral PQRS, PQ = RS = 6 cm and QR = SP = 4 cm.
3 marks
(a)Name the figure PQRS and the test you use.[1]
(b)If ∠P = 65°, find ∠Q, ∠R and ∠S.[2]
Answer and working
(a) PQRS is a parallelogram, because both pairs of opposite sides are equal (PQ = RS and QR = SP).
1 mark
(b) Adjacent angles add up to 180°: ∠Q = 180 − 65 = 115°. Opposite angles are equal: ∠R = ∠P = 65° and ∠S = ∠Q = 115°.
A farmer’s field is the quadrilateral ABCD, with diagonals AC = 80 m and BD = 60 m. He puts poles P, Q, R and S at the midpoints of the sides AB, BC, CD and DA, and joins the poles with a rope to make a smaller field PQRS.
4 marks
(not to scale)
(i)What kind of figure is PQRS?[1]
(ii)Find the lengths PQ and QR.[1]
(iii)Find the length of rope needed to go once round PQRS.[1]
(iv)If the diagonals AC and BD are perpendicular, what special figure is PQRS?[1]
Answer and working
(i) PQRS is a parallelogram (the midpoints of the sides of any quadrilateral form a parallelogram).
1 mark
(ii) PQ = 12 AC = 12 × 80 = 40 m and QR = 12 BD = 12 × 60 = 30 m.
1 mark
(iii) Opposite sides are equal, so the rope needed = 2(40 + 30) = 140 m. This is also AC + BD.
1 mark
(iv) A rectangle.
1 mark
Answer: (i) parallelogram (ii) 40 m and 30 m (iii) 140 m (iv) rectangle
SECTION ELong Answer Questions (5 marks each)10 marks
17
The diagonals of a rhombus ABCD are AC = 16 cm and BD = 12 cm. They meet at O.
5 marks
(a)What is ∠AOB, and why?[1]
(b)Find AO and BO.[1]
(c)Find the side AB.[2]
(d)Find the perimeter of the rhombus.[1]
Answer and working
(a) ∠AOB = 90°, because the diagonals of a rhombus bisect each other at right angles.
1 mark
(b) AO = 12 × 16 = 8 cm and BO = 12 × 12 = 6 cm.
1 mark
(c) Triangle AOB is right-angled at O, so AB² = AO² + BO² = 64 + 36 = 100.
1 mark
AB = 10 cm.
1 mark
(d) All four sides are equal, so the perimeter = 4 × 10 = 40 cm.
1 mark
Answer: (a) 90° (b) 8 cm and 6 cm (c) 10 cm (d) 40 cm
18
Answer these questions on tiling the plane.
5 marks
(a)The angles of a quadrilateral are 85°, 95°, 75° and 105°. Show that four copies of it can fit around a point with no gap and no overlap.[2]
(b)Name one method used to tile the plane with any quadrilateral.[1]
(c)Each angle of a regular polygon is 144°. Can copies of it tile the plane? Give a reason using the angles at a vertex.[2]
Answer and working
(a) 85 + 95 + 75 + 105 = 360. Place one angle of each of four copies around the point, using each angle once. They add up to 360°, so there is no gap and no overlap.
2 marks
(b) Rotate a copy by 180° about the midpoint of a side (it fits exactly along that side), or place copies on alternate parallelograms of the Varignon grid.
1 mark
(c) No. The angles at a vertex must add up to 360°, but 360 ÷ 144 = 2.5 is not a whole number. Two angles give 288° (a gap) and three give 432° (an overlap).
2 marks
Answer: (a) shown (b) rotate about a side’s midpoint (c) no
Key ideas from Chapter 12
Quadrilaterals. The four angles of every quadrilateral add up to 360°. A quadrilateral is convex when every angle is less than 180°. Name it by going round the figure, for example ABCD or BCDA, never ACBD.
Parallelograms. Opposite sides are equal, opposite angles are equal, adjacent angles add up to 180° and the diagonals bisect each other. A quadrilateral is a parallelogram if both pairs of opposite sides are equal, both pairs of opposite angles are equal, the diagonals bisect each other, or one pair of opposite sides is equal and parallel. One pair of parallel sides alone is not enough.
Midpoint Theorem. The segment joining the midpoints of two sides of a triangle is parallel to the third side and half as long. Its converse: a line through the midpoint of one side, parallel to another side, bisects the third side.
Centroid and Varignon parallelogram. The three medians meet at the centroid, which divides each median 2 : 1 from the vertex. The midpoints of the sides of any quadrilateral form a parallelogram whose perimeter is AC + BD. It is a rhombus if AC = BD, a rectangle if AC ⊥ BD, and a square if both.
Tiling. The angles at each vertex of a tiling add up to 360°. Any quadrilateral tiles the plane because its four angles add up to 360°.
Common mistakes to avoid
Treating one pair of parallel sides as enough to prove a parallelogram.
Taking the centroid ratio as 1 : 2 from the vertex. The longer part is towards the vertex.
Thinking the midpoint figure of a rectangle is a rectangle. It is a rhombus.
Frequently asked questions
What is a convex quadrilateral?
A quadrilateral is convex when every internal angle is less than 180 degrees. Its two diagonals intersect. A quadrilateral with a dent, where one angle is more than 180 degrees, is non-convex.
How do I prove that a quadrilateral is a parallelogram?
Show any one of these: both pairs of opposite sides are equal, both pairs of opposite angles are equal, the diagonals bisect each other, or one pair of opposite sides is both equal and parallel.
What does the Midpoint Theorem say?
If P and Q are the midpoints of two sides of a triangle, then PQ is parallel to the third side and equal to half of it.
What is the centroid of a triangle?
The centroid is the point where the three medians meet. It divides each median in the ratio 2 : 1, with the longer part towards the vertex.
Why can any quadrilateral tile the plane?
The four angles of any quadrilateral add up to 360 degrees. So four copies can be placed around a point using each angle once, with no gap and no overlap.
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