NCERT Solutions Class 9 Science Chapter 9 Atomic Foundations of Matter 2026-27. All 51 questions solved - bonding, formulae, mass.
This free NCERT Solutions for CBSE Class IX Science, Chapter 9: Atomic Foundations of Matter, contains step-by-step solutions to every NCERT textbook question and exercise. It has been prepared by Sumeet Sahu at Unique Study Point, Indore, strictly following the latest NCERT syllabus for Session 2026-27.
These are the NCERT Solutions for Class 9 Science Chapter 9, Atomic Foundations of Matter, from the new NCERT Science textbook Exploration (session 2026-27). All 51 questions are solved in simple, exam-ready language, covering the laws of chemical combination, ionic and covalent bonding, chemical formulae, and molecular and formula unit mass.
Water can be obtained from various sources. Are all these samples of water chemically identical?
Pure water is chemically identical everywhere. Water is a compound with a fixed composition: H2O, made of 2 hydrogen atoms and 1 oxygen atom. So pure water (such as distilled water) is the same wherever it comes from.
But the water we get from different sources (river, sea, rain, tap) is not pure. It contains dissolved salts, gases, minerals and other impurities in different amounts, so these samples are not chemically identical.
Oxygen is sometimes represented as O and sometimes as O2. What is the difference between these symbols?
| Symbol | Meaning | Type | Stability |
|---|---|---|---|
| O | A single oxygen atom | Atom | Unstable and very reactive; not found alone in nature |
| O2 | Two oxygen atoms bonded together | Molecule | Stable; the form of oxygen found in air |
Why does dissolved salt in water conduct electricity, but sugar does not?
A student burns 10 g of ethanol in an open beaker. After the reaction, no residue is left in the beaker. Does this mean the Law of Conservation of Mass is violated? Explain.
No, the law is not violated. The law says that mass is neither created nor destroyed in a chemical reaction, so the total mass of reactants equals the total mass of products.
Ethanol burns with the oxygen of the air and forms carbon dioxide and water vapour. These products are gases and escape into the air from the open beaker, so no residue is seen. If we collected all the products, we would find that their mass equals the mass of the ethanol plus the oxygen used.
When 20 g of hydrogen reacts completely with 160 g of oxygen, how much water is formed according to the Law of Conservation of Mass?
180 g of water is formed.
A compound consists of 40% sulfur and 60% oxygen by mass. In a sample of the same compound containing 20 g of sulfur, what mass of oxygen must be present to satisfy the Law of Constant Proportions?
30 g of oxygen must be present.
Carbon monoxide (CO) contains carbon and oxygen in the mass ratio of 3 : 4. How much oxygen will combine with 9 g of carbon to form carbon monoxide?
12 g of oxygen will combine with 9 g of carbon.
The Law of Definite Proportions holds true for compounds but not for mixtures. Give reason.
In a compound, the elements combine chemically in a fixed ratio by mass, so every sample of the compound has the same composition (for example, water always has hydrogen and oxygen in the mass ratio 1 : 8).
In a mixture, the components are only mixed physically and can be present in any proportion (for example, sugar and sand can be mixed in any amounts). So the law does not hold for mixtures.
Students X and Y both prepared an oxide of copper by combining copper and oxygen in the ratios of 4 : 1 and 8 : 2, respectively. Do their results justify the Law of Constant Proportions? Explain.
| Student | Cu : O | Simplified |
|---|---|---|
| X | 4 : 1 | 4 : 1 |
| Y | 8 : 2 | 4 : 1 (divide both terms by 2) |
Yes. Both ratios simplify to 4 : 1. The same compound contains the same elements in a fixed ratio by mass, so the results justify the Law of Constant Proportions.
What if atoms could combine in any ratio and not in a fixed ratio? How would this affect the substances around us?
Substances would not have a definite composition. Different samples of the same substance (such as water or carbon dioxide) would contain different amounts of their elements, so the Law of Constant Proportions would not hold.
The properties of substances, such as melting point, boiling point and density, would change from sample to sample. Substances would be unreliable and unpredictable, and chemistry could not be studied in a systematic way.
Assertion (A): 2 g of hydrogen combines with 16 g of oxygen to form 18 g of water.
Reason (R): According to Dalton’s Atomic Theory, atoms combine in a simple whole number ratio to form compounds.
Correct option: (a)
Both are true and R explains A. Atoms of hydrogen and oxygen combine in a fixed simple ratio (2 : 1), which gives the fixed mass ratio of 1 : 8 (2 g : 16 g). So water always has the same composition.
Nitrogen has five valence electrons. Draw the structure of the nitrogen molecule (N2).
Each nitrogen atom needs 3 more electrons to complete its octet. So two nitrogen atoms share three pairs of electrons and form a triple covalent bond.
:N ≡ N:The atomic number of fluorine is 9. Explain the formation of the fluorine molecule (F2).
The electronic configuration of fluorine is 2, 7. Each fluorine atom has 7 valence electrons and needs 1 more electron to complete its octet.
Two fluorine atoms share one pair of electrons and form a single covalent bond, so each atom gets a stable octet.
F – F (each atom has 3 lone pairs and 1 shared pair)Show the formation of the following molecules: (i) carbon dioxide (CO2), (ii) hydrogen sulfide (H2S), (iii) ammonia (NH3).
(i) Carbon dioxide (CO2): carbon has 4 valence electrons and each oxygen has 6. Carbon shares 2 electrons with each oxygen, forming two double covalent bonds. The molecule is linear (O=C=O) and every atom has a complete octet.
(ii) Hydrogen sulfide (H2S): sulfur has 6 valence electrons and each hydrogen has 1. Sulfur shares 1 electron with each hydrogen, forming two single bonds and keeping two lone pairs. The shape is bent (V-shaped).
(iii) Ammonia (NH3): nitrogen has 5 valence electrons and each hydrogen has 1. Nitrogen shares 1 electron with each of three hydrogen atoms, forming three single bonds and keeping one lone pair. The shape is trigonal pyramidal.
Neon (atomic number 10) neither transfers nor shares its valence electrons. Explain.
The electronic configuration of neon is 2, 8. Its outermost shell is already completely filled (an octet), which makes it very stable. So neon does not need to gain, lose or share electrons, and it does not usually form chemical bonds.
What if we could see atoms directly? How would it help scientists and what challenges would it cause?
Help: scientists could see how atoms are arranged and combine and how reactions take place at the atomic level. This would help in understanding bonding and molecular structure and in designing new materials and medicines more accurately.
Challenges: atoms are extremely small and in constant motion, so it would need very powerful and costly technology, and it would still be hard to measure their motion and behaviour precisely.
What kind of ion will oxygen (O) form?
Oxygen has atomic number 8 and electronic configuration 2, 6. It has 6 valence electrons and needs 2 more to complete its octet. So it gains 2 electrons and forms a negative ion, the oxide ion (O2−).
Fill in the blanks: Among magnesium and chlorine, a magnesium atom can give two electrons to become Mg2+. However, chlorine can take only one electron to become ________. Now, ________ ion of magnesium and ________ ions of chlorine combine to give magnesium chloride.
Answers: Cl−; one (Mg2+); two (Cl−)
One Mg2+ ion combines with two Cl− ions to give MgCl2.
Show the formation of cations of potassium (K) and calcium (Ca) atoms, and the formation of their corresponding chlorides using diagrams.
| Atom | Electronic configuration | Change | Ion formed |
|---|---|---|---|
| Potassium (K) | 2, 8, 8, 1 | loses 1 electron | K+ (2, 8, 8) |
| Calcium (Ca) | 2, 8, 8, 2 | loses 2 electrons | Ca2+ (2, 8, 8) |
| Chlorine (Cl) | 2, 8, 7 | gains 1 electron | Cl− (2, 8, 8) |
Diagram: draw the shell diagram of each atom, with arrows showing the electrons moving from K or Ca to Cl, and then the ions with their charges.
Illustrate how sodium sulfide (Na2S) is formed.
Name the following: (i) CO2, (ii) NO2, (iii) SF6, (iv) PCl3.
| Formula | Name |
|---|---|
| (i) CO2 | Carbon dioxide |
| (ii) NO2 | Nitrogen dioxide |
| (iii) SF6 | Sulfur hexafluoride |
| (iv) PCl3 | Phosphorus trichloride |
Write the formulae for the compounds formed from the following pairs of ions: (i) Fe3+ and OH−, (ii) K+ and CO32−.
What type of chemical bond is present in a solid compound that does not conduct electricity in the solid state but conducts electricity when dissolved in water?
The compound has an ionic bond. In the solid state the ions are fixed in a crystal lattice and cannot move, so it does not conduct electricity. When dissolved in water, the compound splits into free ions that can move and carry current, so the solution conducts electricity.
Metal M, with two electrons in its valence shell, reacts with oxygen to form a compound that is slightly soluble in water. Predict its (i) formula, (ii) type of bond, (iii) electrical conductivity of its aqueous solution.
Find the molecular mass of nitric acid (HNO3). Atomic mass: H = 1 u; N = 14 u; O = 16 u.
Molecular mass of HNO3 = 63 u
Find the molecular mass of methane (CH4). Atomic mass: C = 12 u; H = 1 u.
Molecular mass of CH4 = 16 u
Find the formula unit mass of potassium chloride (KCl). Atomic mass: K = 39 u; Cl = 35.5 u.
Formula unit mass of KCl = 74.5 u
Find the formula unit mass of magnesium hydroxide, Mg(OH)2. Atomic mass: Mg = 24 u; O = 16 u; H = 1 u.
Formula unit mass of Mg(OH)2 = 58 u
In a group activity, students place 4.0 g of calcium carbonate with 2.92 g of hydrochloric acid in a closed container. After the reaction is over, they measured 1.76 g of carbon dioxide, 0.72 g of water, and 4.44 g of calcium chloride. Verify whether the Law of Conservation of Mass is obeyed or not.
| Substances | Total mass | |
|---|---|---|
| Reactants | 4.0 g + 2.92 g | 6.92 g |
| Products | 1.76 g + 0.72 g + 4.44 g | 6.92 g |
Mass of reactants = mass of products, so the Law of Conservation of Mass is obeyed.
12 g of carbon combines with 32 g of oxygen to form 44 g of carbon dioxide (carbon + oxygen → carbon dioxide). If 2.4 g of carbon reacts completely with oxygen, how much carbon dioxide will be produced?
8.8 g of carbon dioxide will be produced.
Sodium chloride (NaCl) contains sodium and chlorine in the mass ratio of 23 : 35.5. If 46 g of sodium reacts completely, how much chlorine is needed to form NaCl?
71 g of chlorine is needed.
Find the molecular mass of water (H2O). Atomic mass: H = 1 u; O = 16 u.
Molecular mass of H2O = 18 u
Find the molecular mass of carbon dioxide (CO2). Atomic mass: C = 12 u; O = 16 u.
Molecular mass of CO2 = 44 u
Find the formula unit mass of sodium oxide (Na2O). Atomic mass: Na = 23 u; O = 16 u.
Formula unit mass of Na2O = 62 u
Find the formula unit mass of calcium nitrate, Ca(NO3)2. Atomic mass: Ca = 40 u; N = 14 u; O = 16 u.
Formula unit mass of Ca(NO3)2 = 164 u
A particular element (A) has one electron in its third shell. There is another element (B) with six electrons in its second shell. (i) How many electrons does A tend to give or take to become stable? (ii) What kind of ion would it form? (iii) How many electrons does B tend to give or take to become stable? (iv) What kind of ion would it form? (v) If A and B were to combine, what kind of bond would be formed? (vi) What would be the formula for the compound thus formed?
| Part | Answer | Reason |
|---|---|---|
| (i) | A gives 1 electron | Configuration 2, 8, 1: losing 1 electron leaves a full shell |
| (ii) | A+ (cation) | It loses a negative charge |
| (iii) | B takes 2 electrons | Configuration 2, 6: it needs 2 more for an octet |
| (iv) | B2− (anion) | It gains two negative charges |
| (v) | Ionic bond | A transfers electrons to B |
| (vi) | A2B | Two A+ ions balance one B2− ion |
An element X has six electrons in its outer shell and forms a diatomic molecule. (i) Why would that be so? (ii) What kind of bond would it form? (iii) Draw the structure of the molecule it would form. (iv) A certain other element Y has two electrons in its second shell. Draw the structure of the molecule that X would form with Y.
(i) X needs 2 more electrons to complete its octet. Two atoms of X share electrons with each other, so each atom completes its octet and forms a diatomic molecule (X2).
(ii) Electrons are shared, so it is a covalent bond, and it is a double bond (two pairs are shared).
(iii) Structure:
X = X (each X atom also has 2 lone pairs)(iv) Y has 2 electrons in its second shell, so it loses these 2 electrons to form Y2+. X gains 2 electrons to form X2−. One Y atom combines with one X atom.
Y2+ + X2− → YX (ionic compound)You want to design a new ionic compound, where the total positive charge is 6+ and the total negative charge is 6−. Which of the following combinations gives the correct number of ions?
Correct option: (a) 2Fe3+ and 3O2−
2 × (+3) = +6 and 3 × (−2) = −6, so the total positive and negative charges are equal. In (b) the charges are +6 and −4, in (c) +6 and −3, and in (d) +6 and −3, so they are not balanced.
Choose the correct statement(s) and correct the false statement(s). (i) Elements are made up of molecules and compounds are made up of atoms. (ii) The molecule of a compound is always made up of two or more atoms of the same kind. (iii) One molecule of nitrogen gas contains three nitrogen atoms. (iv) Water is made of two hydrogen atoms, covalently bonded with one oxygen atom.
| Statement | True or false | Correction |
|---|---|---|
| (i) | False | Elements are made up of only one kind of atom (as atoms or molecules), and compounds are made up of two or more different kinds of atoms chemically combined |
| (ii) | False | The molecule of a compound is made up of two or more atoms of different kinds |
| (iii) | False | One molecule of nitrogen gas (N2) contains two nitrogen atoms |
| (iv) | True | Water (H2O) has two hydrogen atoms covalently bonded to one oxygen atom |
Write the chemical formulae for the following compounds: (i) aluminium nitrate, (ii) calcium oxide, (iii) ferric oxide.
| Compound | Ions | Balancing | Formula |
|---|---|---|---|
| (i) Aluminium nitrate | Al3+, NO3− | 1 Al3+ needs 3 NO3− | Al(NO3)3 |
| (ii) Calcium oxide | Ca2+, O2− | 1 : 1 | CaO |
| (iii) Ferric oxide | Fe3+, O2− | 2 Fe3+ (6+) and 3 O2− (6−) | Fe2O3 |
Write the formulae of the compounds formed from the following pairs of ions: (i) Ca2+ and Br−, (ii) Al3+ and CO32−, (iii) K+ and SO42−, (iv) NH4+ and Cl−.
| Ions | Balancing | Formula |
|---|---|---|
| (i) Ca2+, Br− | 1 Ca2+ needs 2 Br− | CaBr2 |
| (ii) Al3+, CO32− | 2 Al3+ (6+) and 3 CO32− (6−) | Al2(CO3)3 |
| (iii) K+, SO42− | 2 K+ balance 1 SO42− | K2SO4 |
| (iv) NH4+, Cl− | 1 : 1 | NH4Cl |
Which of the following in the figure correctly represents the Cl− ion (atomic number of chlorine = 17)?
Diagram (ii), which shows 18 electrons, represents the Cl− ion.
Determine the formula unit mass of the following substances: (i) ammonium nitrate (NH4NO3), (ii) phosphoric acid (H3PO4), (iii) sodium hydrogencarbonate (NaHCO3). (Atomic mass: N = 14, H = 1, O = 16, P = 31, Na = 23, C = 12.)
| Substance | Calculation | Mass |
|---|---|---|
| (i) NH4NO3 | (2 × 14) + (4 × 1) + (3 × 16) = 28 + 4 + 48 | 80 u |
| (ii) H3PO4 | (3 × 1) + 31 + (4 × 16) = 3 + 31 + 64 | 98 u |
| (iii) NaHCO3 | 23 + 1 + 12 + (3 × 16) = 23 + 1 + 12 + 48 | 84 u |
Write the formulae for the compounds formed by the reaction of: (i) magnesium and nitrogen, (ii) lithium and nitrogen, (iii) sodium and sulfur, (iv) aluminium and oxygen.
| Reaction | Ions | Balancing | Formula |
|---|---|---|---|
| (i) Mg and N | Mg2+, N3− | 3 Mg2+ (6+) and 2 N3− (6−) | Mg3N2 |
| (ii) Li and N | Li+, N3− | 3 Li+ and 1 N3− | Li3N |
| (iii) Na and S | Na+, S2− | 2 Na+ and 1 S2− | Na2S |
| (iv) Al and O | Al3+, O2− | 2 Al3+ (6+) and 3 O2− (6−) | Al2O3 |
Complete the table by writing the formulae of the compounds formed by the cations on the left and the anions at the top. LiNO3 is given as an example.
| NO3− | SO42− | PO43− | |
|---|---|---|---|
| NH4+ | |||
| Li+ | LiNO3 | ||
| Al3+ | |||
| Cu2+ |
| NO3− | SO42− | PO43− | |
|---|---|---|---|
| NH4+ | NH4NO3 | (NH4)2SO4 | (NH4)3PO4 |
| Li+ | LiNO3 | Li2SO4 | Li3PO4 |
| Al3+ | Al(NO3)3 | Al2(SO4)3 | AlPO4 |
| Cu2+ | Cu(NO3)2 | CuSO4 | Cu3(PO4)2 |
5.3 g of sodium carbonate and 6.0 g of acetic acid react to produce 2.2 g of carbon dioxide, 0.9 g of water, and 8.2 g of sodium acetate. Verify whether the law of conservation of mass is valid.
| Substances | Total mass | |
|---|---|---|
| Reactants | 5.3 g + 6.0 g | 11.3 g |
| Products | 2.2 g + 0.9 g + 8.2 g | 11.3 g |
Mass of reactants = mass of products, so the law of conservation of mass is valid.
If a species has 11 protons, 12 neutrons and 10 electrons, then (i) what is its atomic number and mass number? (ii) is it neutral, a cation or an anion? Explain. (iii) write its electronic configuration. (iv) name the species.
| Part | Answer | Explanation |
|---|---|---|
| (i) | Atomic number = 11, mass number = 23 | Atomic number = protons; mass number = 11 + 12 |
| (ii) | Cation (charge +1) | It has 11 protons but only 10 electrons, so it has lost one electron |
| (iii) | 2, 8 | It has 10 electrons in total |
| (iv) | Sodium ion (Na+) | Atomic number 11 is sodium, and it has lost 1 electron |
Two elements, A and B, have the following configurations: A: 2, 8, 5 and B: 2, 8, 7. (i) Which element is more reactive? (ii) Will A and B form ionic or covalent bonds when they combine? Explain using electron transfer or sharing. (iii) Predict the formula of the compound they would form.
Assertion (A): Copper sulfate conducts electricity in the molten state but not in the solid state.
Reason (R): Copper and sulfate ions are fixed in the lattice in molten state, while in solid state they can move freely.
Correct option: (c)
The species 27Al, 80Br− and 201Hg2+ have 13, 35 and 80 protons, respectively. How many electrons and neutrons do they have?
| Species | Protons | Electrons | Neutrons |
|---|---|---|---|
| 27Al (neutral) | 13 | 13 | 27 − 13 = 14 |
| 80Br− (gained 1 electron) | 35 | 35 + 1 = 36 | 80 − 35 = 45 |
| 201Hg2+ (lost 2 electrons) | 80 | 80 − 2 = 78 | 201 − 80 = 121 |
Are there any chemical changes that do not obey the Law of Conservation of Mass?
No. In every chemical reaction mass is conserved; it is neither created nor destroyed. Sometimes the mass seems to change because the reaction takes place in an open system, where gases can escape or enter. In a closed system, the total mass of the reactants is always equal to the total mass of the products.
All 51 questions of Chapter 9, Atomic Foundations of Matter, from the new NCERT Exploration textbook (2026-27) are solved on this page.
In an ionic bond, electrons are transferred from one atom to another to form ions. In a covalent bond, atoms share pairs of electrons.
Write the symbols of the ions with their charges and balance the total positive charge and the total negative charge, for example, Al3+ and O2− give Al2O3.
Multiply the atomic mass of each element by the number of its atoms in the formula and add them up. For example, H2O = (2 × 1) + 16 = 18 u.
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Solutions prepared by Unique Study Point by Sumeet Sahu. Figures are from the NCERT Science textbook Exploration (Class 9).
| Class | Class IX (CBSE / NCERT) |
| Subject | Science |
| Chapter | Chapter 9: Atomic Foundations of Matter |
| Resource Type | NCERT Solutions |
| Last Updated | 26 October 2026 |
| Session | 2026-27 (Latest NCERT Syllabus) |
| Downloads | 1+ |
| Prepared by | Sumeet Sahu, Unique Study Point, Indore |
| Cost | Free |