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NCERT Solutions Class 9 Science Ch 9 Matter 2026-27

NCERT Solutions Class 9 Science Chapter 9 Atomic Foundations of Matter 2026-27. All 51 questions solved - bonding, formulae, mass.

This free NCERT Solutions for CBSE Class IX Science, Chapter 9: Atomic Foundations of Matter, contains step-by-step solutions to every NCERT textbook question and exercise. It has been prepared by Sumeet Sahu at Unique Study Point, Indore, strictly following the latest NCERT syllabus for Session 2026-27.

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These are the NCERT Solutions for Class 9 Science Chapter 9, Atomic Foundations of Matter, from the new NCERT Science textbook Exploration (session 2026-27). All 51 questions are solved in simple, exam-ready language, covering the laws of chemical combination, ionic and covalent bonding, chemical formulae, and molecular and formula unit mass.

Class
9 (IX)
Subject
Science
Textbook
Exploration (NCERT, 2026-27)
Chapter
9 – Atomic Foundations of Matter
Questions solved
51
Jump to a question (51 questions)

NCERT Class 9 Science Chapter 9 Questions and Answers

Question 1: Are all samples of water chemically identical?

Q13 marks

Water can be obtained from various sources. Are all these samples of water chemically identical?

Answer

Pure water is chemically identical everywhere. Water is a compound with a fixed composition: H2O, made of 2 hydrogen atoms and 1 oxygen atom. So pure water (such as distilled water) is the same wherever it comes from.

But the water we get from different sources (river, sea, rain, tap) is not pure. It contains dissolved salts, gases, minerals and other impurities in different amounts, so these samples are not chemically identical.

Question 2: Difference between the symbols O and O2

Q22 marks

Oxygen is sometimes represented as O and sometimes as O2. What is the difference between these symbols?

Answer
SymbolMeaningTypeStability
OA single oxygen atomAtomUnstable and very reactive; not found alone in nature
O2Two oxygen atoms bonded togetherMoleculeStable; the form of oxygen found in air

Question 3: Why does salt solution conduct electricity but sugar solution does not?

Q33 marks

Why does dissolved salt in water conduct electricity, but sugar does not?

Answer
  • Salt (NaCl) is an ionic compound. In water it breaks into free ions, NaCl → Na+ + Cl−. These moving ions carry charge, so the solution conducts electricity.
  • Sugar is a covalent compound. In water it stays as neutral molecules and forms no ions. With no charged particles, it cannot conduct electricity.

Question 4: Burning ethanol in an open beaker and the law of conservation of mass

Q43 marks

A student burns 10 g of ethanol in an open beaker. After the reaction, no residue is left in the beaker. Does this mean the Law of Conservation of Mass is violated? Explain.

Answer

No, the law is not violated. The law says that mass is neither created nor destroyed in a chemical reaction, so the total mass of reactants equals the total mass of products.

Ethanol burns with the oxygen of the air and forms carbon dioxide and water vapour. These products are gases and escape into the air from the open beaker, so no residue is seen. If we collected all the products, we would find that their mass equals the mass of the ethanol plus the oxygen used.

Question 5: Mass of water formed from hydrogen and oxygen

Q53 marks

When 20 g of hydrogen reacts completely with 160 g of oxygen, how much water is formed according to the Law of Conservation of Mass?

Answer
  1. Law of conservation of massMass of reactants = mass of products
  2. Mass of water20 g + 160 g = 180 g

180 g of water is formed.

Question 6: Oxygen needed for 20 g of sulfur (law of constant proportions)

Q63 marks

A compound consists of 40% sulfur and 60% oxygen by mass. In a sample of the same compound containing 20 g of sulfur, what mass of oxygen must be present to satisfy the Law of Constant Proportions?

Answer
  1. Mass ratioS : O = 40 : 60 = 2 : 3
  2. Calculation2 parts of sulfur = 20 g, so 1 part = 10 g.Oxygen = 3 × 10 = 30 g

30 g of oxygen must be present.

Question 7: Oxygen that combines with 9 g of carbon in CO

Q73 marks

Carbon monoxide (CO) contains carbon and oxygen in the mass ratio of 3 : 4. How much oxygen will combine with 9 g of carbon to form carbon monoxide?

Answer
  1. One part3 parts of carbon = 9 g, so 1 part = 3 g
  2. Oxygen (4 parts)4 × 3 = 12 g

12 g of oxygen will combine with 9 g of carbon.

Question 8: Law of definite proportions: compounds and mixtures

Q82 marks

The Law of Definite Proportions holds true for compounds but not for mixtures. Give reason.

Answer

In a compound, the elements combine chemically in a fixed ratio by mass, so every sample of the compound has the same composition (for example, water always has hydrogen and oxygen in the mass ratio 1 : 8).

In a mixture, the components are only mixed physically and can be present in any proportion (for example, sugar and sand can be mixed in any amounts). So the law does not hold for mixtures.

Question 9: Do the copper oxide results of students X and Y justify the law?

Q92 marks

Students X and Y both prepared an oxide of copper by combining copper and oxygen in the ratios of 4 : 1 and 8 : 2, respectively. Do their results justify the Law of Constant Proportions? Explain.

Answer
StudentCu : OSimplified
X4 : 14 : 1
Y8 : 24 : 1 (divide both terms by 2)

Yes. Both ratios simplify to 4 : 1. The same compound contains the same elements in a fixed ratio by mass, so the results justify the Law of Constant Proportions.

Question 10: What if atoms could combine in any ratio?

Q103 marks

What if atoms could combine in any ratio and not in a fixed ratio? How would this affect the substances around us?

Answer

Substances would not have a definite composition. Different samples of the same substance (such as water or carbon dioxide) would contain different amounts of their elements, so the Law of Constant Proportions would not hold.

The properties of substances, such as melting point, boiling point and density, would change from sample to sample. Substances would be unreliable and unpredictable, and chemistry could not be studied in a systematic way.

Question 11: Assertion-reason: hydrogen and oxygen forming water

Q111 mark

Assertion (A): 2 g of hydrogen combines with 16 g of oxygen to form 18 g of water.

Reason (R): According to Dalton’s Atomic Theory, atoms combine in a simple whole number ratio to form compounds.

  1. Both A and R are true and R is the correct explanation of A.
  2. Both A and R are true but R is not the correct explanation of A.
  3. A is true but R is false.
  4. A is false but R is true.
Answer

Correct option: (a)

Both are true and R explains A. Atoms of hydrogen and oxygen combine in a fixed simple ratio (2 : 1), which gives the fixed mass ratio of 1 : 8 (2 g : 16 g). So water always has the same composition.

Question 12: Structure of the nitrogen molecule (N2)

Q123 marks

Nitrogen has five valence electrons. Draw the structure of the nitrogen molecule (N2).

Answer

Each nitrogen atom needs 3 more electrons to complete its octet. So two nitrogen atoms share three pairs of electrons and form a triple covalent bond.

:N ≡ N:
  • Each nitrogen atom has 3 shared pairs (the triple bond) and 1 lone pair.
  • Each atom now has 8 electrons around it (an octet).

Question 13: Formation of the fluorine molecule (F2)

Q133 marks

The atomic number of fluorine is 9. Explain the formation of the fluorine molecule (F2).

Answer

The electronic configuration of fluorine is 2, 7. Each fluorine atom has 7 valence electrons and needs 1 more electron to complete its octet.

Two fluorine atoms share one pair of electrons and form a single covalent bond, so each atom gets a stable octet.

F – F (each atom has 3 lone pairs and 1 shared pair)

Question 14: Formation of CO2, H2S and NH3

Q145 marks

Show the formation of the following molecules: (i) carbon dioxide (CO2), (ii) hydrogen sulfide (H2S), (iii) ammonia (NH3).

Answer

(i) Carbon dioxide (CO2): carbon has 4 valence electrons and each oxygen has 6. Carbon shares 2 electrons with each oxygen, forming two double covalent bonds. The molecule is linear (O=C=O) and every atom has a complete octet.

Structure of carbon dioxide: an oxygen atom with two lone pairs double bonded to carbon, which is double bonded to a second oxygen atom

(ii) Hydrogen sulfide (H2S): sulfur has 6 valence electrons and each hydrogen has 1. Sulfur shares 1 electron with each hydrogen, forming two single bonds and keeping two lone pairs. The shape is bent (V-shaped).

Structure of hydrogen sulfide: a sulfur atom with two lone pairs joined by single bonds to two hydrogen atoms

(iii) Ammonia (NH3): nitrogen has 5 valence electrons and each hydrogen has 1. Nitrogen shares 1 electron with each of three hydrogen atoms, forming three single bonds and keeping one lone pair. The shape is trigonal pyramidal.

Structure of ammonia: a nitrogen atom with one lone pair bonded to three hydrogen atoms in a trigonal pyramidal shape, with a bond angle of 107 degrees
Structure of ammonia drawn with single bonds from nitrogen to three hydrogen atoms

Question 15: Why neon neither transfers nor shares electrons

Q152 marks

Neon (atomic number 10) neither transfers nor shares its valence electrons. Explain.

Answer

The electronic configuration of neon is 2, 8. Its outermost shell is already completely filled (an octet), which makes it very stable. So neon does not need to gain, lose or share electrons, and it does not usually form chemical bonds.

Question 16: What if we could see atoms directly?

Q162 marks

What if we could see atoms directly? How would it help scientists and what challenges would it cause?

Answer

Help: scientists could see how atoms are arranged and combine and how reactions take place at the atomic level. This would help in understanding bonding and molecular structure and in designing new materials and medicines more accurately.

Challenges: atoms are extremely small and in constant motion, so it would need very powerful and costly technology, and it would still be hard to measure their motion and behaviour precisely.

Question 17: What kind of ion will oxygen form?

Q173 marks

What kind of ion will oxygen (O) form?

Answer

Oxygen has atomic number 8 and electronic configuration 2, 6. It has 6 valence electrons and needs 2 more to complete its octet. So it gains 2 electrons and forms a negative ion, the oxide ion (O2−).

Question 18: Fill in the blanks: magnesium chloride

Q181 mark

Fill in the blanks: Among magnesium and chlorine, a magnesium atom can give two electrons to become Mg2+. However, chlorine can take only one electron to become ________. Now, ________ ion of magnesium and ________ ions of chlorine combine to give magnesium chloride.

Answer

Answers: Cl−; one (Mg2+); two (Cl−)

One Mg2+ ion combines with two Cl− ions to give MgCl2.

Question 19: Formation of K+, Ca2+ and their chlorides

Q193 marks

Show the formation of cations of potassium (K) and calcium (Ca) atoms, and the formation of their corresponding chlorides using diagrams.

Answer
AtomElectronic configurationChangeIon formed
Potassium (K)2, 8, 8, 1loses 1 electronK+ (2, 8, 8)
Calcium (Ca)2, 8, 8, 2loses 2 electronsCa2+ (2, 8, 8)
Chlorine (Cl)2, 8, 7gains 1 electronCl− (2, 8, 8)
  • Potassium chloride: K loses 1 electron to form K+ and Cl gains it to form Cl−. One K+ and one Cl− give KCl.
  • Calcium chloride: Ca loses 2 electrons to form Ca2+, and each of two Cl atoms gains 1 electron to form 2 Cl−. One Ca2+ and two Cl− give CaCl2.

Diagram: draw the shell diagram of each atom, with arrows showing the electrons moving from K or Ca to Cl, and then the ions with their charges.

Question 20: Formation of sodium sulfide (Na2S)

Q202 marks

Illustrate how sodium sulfide (Na2S) is formed.

Answer
  • Sodium (2, 8, 1) loses 1 electron to form Na+ (2, 8).
  • Sulfur (2, 8, 6) needs 2 electrons to complete its octet, so it gains 2 electrons to form S2− (2, 8, 8).
  • One sulfur atom needs 2 electrons, so two sodium atoms each give 1 electron.
2Na+ + S2− → Na2S

Question 21: Naming CO2, NO2, SF6 and PCl3

Q212 marks

Name the following: (i) CO2, (ii) NO2, (iii) SF6, (iv) PCl3.

Answer
FormulaName
(i) CO2Carbon dioxide
(ii) NO2Nitrogen dioxide
(iii) SF6Sulfur hexafluoride
(iv) PCl3Phosphorus trichloride

Question 22: Formulae from pairs of ions

Q222 marks

Write the formulae for the compounds formed from the following pairs of ions: (i) Fe3+ and OH−, (ii) K+ and CO32−.

Answer
  • (i) One Fe3+ needs 3 OH− to balance the charge. Formula: Fe(OH)3
  • (ii) One CO32− needs 2 K+ to balance the charge. Formula: K2CO3

Question 23: Bond in a solid that conducts only when dissolved in water

Q233 marks

What type of chemical bond is present in a solid compound that does not conduct electricity in the solid state but conducts electricity when dissolved in water?

Answer

The compound has an ionic bond. In the solid state the ions are fixed in a crystal lattice and cannot move, so it does not conduct electricity. When dissolved in water, the compound splits into free ions that can move and carry current, so the solution conducts electricity.

Question 24: Compound of a metal M with two valence electrons and oxygen

Q243 marks

Metal M, with two electrons in its valence shell, reacts with oxygen to form a compound that is slightly soluble in water. Predict its (i) formula, (ii) type of bond, (iii) electrical conductivity of its aqueous solution.

Answer
  • (i) Formula: M loses 2 electrons to form M2+, and oxygen gains 2 electrons to form O2−. The charges balance in a 1 : 1 ratio, so the formula is MO.
  • (ii) Type of bond: electrons are transferred from the metal to the non-metal, so it is an ionic bond.
  • (iii) Conductivity: the compound gives M2+ and O2− ions in water, and these ions move freely, so the solution conducts electricity (weakly, as only a little of it dissolves).

Question 25: Molecular mass of nitric acid (HNO3)

Q252 marks

Find the molecular mass of nitric acid (HNO3). Atomic mass: H = 1 u; N = 14 u; O = 16 u.

Answer(1 × 1) + (1 × 14) + (3 × 16) = 1 + 14 + 48 = 63 u

Molecular mass of HNO3 = 63 u

Question 26: Molecular mass of methane (CH4)

Q262 marks

Find the molecular mass of methane (CH4). Atomic mass: C = 12 u; H = 1 u.

Answer(1 × 12) + (4 × 1) = 12 + 4 = 16 u

Molecular mass of CH4 = 16 u

Question 27: Formula unit mass of potassium chloride (KCl)

Q272 marks

Find the formula unit mass of potassium chloride (KCl). Atomic mass: K = 39 u; Cl = 35.5 u.

Answer39 + 35.5 = 74.5 u

Formula unit mass of KCl = 74.5 u

Question 28: Formula unit mass of magnesium hydroxide, Mg(OH)2

Q282 marks

Find the formula unit mass of magnesium hydroxide, Mg(OH)2. Atomic mass: Mg = 24 u; O = 16 u; H = 1 u.

Answer24 + (2 × 16) + (2 × 1) = 24 + 32 + 2 = 58 u

Formula unit mass of Mg(OH)2 = 58 u

Question 29: Verifying the law of conservation of mass: CaCO3 and HCl

Q292 marks

In a group activity, students place 4.0 g of calcium carbonate with 2.92 g of hydrochloric acid in a closed container. After the reaction is over, they measured 1.76 g of carbon dioxide, 0.72 g of water, and 4.44 g of calcium chloride. Verify whether the Law of Conservation of Mass is obeyed or not.

Answer
SubstancesTotal mass
Reactants4.0 g + 2.92 g6.92 g
Products1.76 g + 0.72 g + 4.44 g6.92 g

Mass of reactants = mass of products, so the Law of Conservation of Mass is obeyed.

Question 30: Carbon dioxide formed from 2.4 g of carbon

Q302 marks

12 g of carbon combines with 32 g of oxygen to form 44 g of carbon dioxide (carbon + oxygen → carbon dioxide). If 2.4 g of carbon reacts completely with oxygen, how much carbon dioxide will be produced?

Answer
  1. For 1 g of carbon44 ÷ 12 g of carbon dioxide
  2. For 2.4 g of carbon(44 ÷ 12) × 2.4 = 8.8 g

8.8 g of carbon dioxide will be produced.

Question 31: Chlorine needed for 46 g of sodium

Q312 marks

Sodium chloride (NaCl) contains sodium and chlorine in the mass ratio of 23 : 35.5. If 46 g of sodium reacts completely, how much chlorine is needed to form NaCl?

AnswerChlorine = (35.5 ÷ 23) × 46 = 35.5 × 2 = 71 g

71 g of chlorine is needed.

Question 32: Molecular mass of water (H2O)

Q322 marks

Find the molecular mass of water (H2O). Atomic mass: H = 1 u; O = 16 u.

Answer(2 × 1) + (1 × 16) = 18 u

Molecular mass of H2O = 18 u

Question 33: Molecular mass of carbon dioxide (CO2)

Q332 marks

Find the molecular mass of carbon dioxide (CO2). Atomic mass: C = 12 u; O = 16 u.

Answer(1 × 12) + (2 × 16) = 44 u

Molecular mass of CO2 = 44 u

Question 34: Formula unit mass of sodium oxide (Na2O)

Q342 marks

Find the formula unit mass of sodium oxide (Na2O). Atomic mass: Na = 23 u; O = 16 u.

Answer(2 × 23) + (1 × 16) = 62 u

Formula unit mass of Na2O = 62 u

Question 35: Formula unit mass of calcium nitrate, Ca(NO3)2

Q352 marks

Find the formula unit mass of calcium nitrate, Ca(NO3)2. Atomic mass: Ca = 40 u; N = 14 u; O = 16 u.

Answer40 + 2 × (14 + 3 × 16) = 40 + 2 × 62 = 164 u

Formula unit mass of Ca(NO3)2 = 164 u

Question 36: Elements A and B and the compound they form

Q365 marks

A particular element (A) has one electron in its third shell. There is another element (B) with six electrons in its second shell. (i) How many electrons does A tend to give or take to become stable? (ii) What kind of ion would it form? (iii) How many electrons does B tend to give or take to become stable? (iv) What kind of ion would it form? (v) If A and B were to combine, what kind of bond would be formed? (vi) What would be the formula for the compound thus formed?

Answer
PartAnswerReason
(i)A gives 1 electronConfiguration 2, 8, 1: losing 1 electron leaves a full shell
(ii)A+ (cation)It loses a negative charge
(iii)B takes 2 electronsConfiguration 2, 6: it needs 2 more for an octet
(iv)B2− (anion)It gains two negative charges
(v)Ionic bondA transfers electrons to B
(vi)A2BTwo A+ ions balance one B2− ion

Question 37: Diatomic molecule of an element with six valence electrons

Q375 marks

An element X has six electrons in its outer shell and forms a diatomic molecule. (i) Why would that be so? (ii) What kind of bond would it form? (iii) Draw the structure of the molecule it would form. (iv) A certain other element Y has two electrons in its second shell. Draw the structure of the molecule that X would form with Y.

Answer

(i) X needs 2 more electrons to complete its octet. Two atoms of X share electrons with each other, so each atom completes its octet and forms a diatomic molecule (X2).

(ii) Electrons are shared, so it is a covalent bond, and it is a double bond (two pairs are shared).

(iii) Structure:

X = X (each X atom also has 2 lone pairs)

(iv) Y has 2 electrons in its second shell, so it loses these 2 electrons to form Y2+. X gains 2 electrons to form X2−. One Y atom combines with one X atom.

Y2+ + X2− → YX (ionic compound)

Question 38: Combination of ions with total charge 6+ and 6−

Q381 mark

You want to design a new ionic compound, where the total positive charge is 6+ and the total negative charge is 6−. Which of the following combinations gives the correct number of ions?

  1. 2Fe3+ and 3O2−
  2. 3Ca2+ and 2SO42−
  3. 3Mg2+ and 1PO43−
  4. 2Al3+ and 3Cl−
Answer

Correct option: (a) 2Fe3+ and 3O2−

2 × (+3) = +6 and 3 × (−2) = −6, so the total positive and negative charges are equal. In (b) the charges are +6 and −4, in (c) +6 and −3, and in (d) +6 and −3, so they are not balanced.

Question 39: Correct or false statements on elements, compounds and molecules

Q392 marks

Choose the correct statement(s) and correct the false statement(s). (i) Elements are made up of molecules and compounds are made up of atoms. (ii) The molecule of a compound is always made up of two or more atoms of the same kind. (iii) One molecule of nitrogen gas contains three nitrogen atoms. (iv) Water is made of two hydrogen atoms, covalently bonded with one oxygen atom.

Answer
StatementTrue or falseCorrection
(i)FalseElements are made up of only one kind of atom (as atoms or molecules), and compounds are made up of two or more different kinds of atoms chemically combined
(ii)FalseThe molecule of a compound is made up of two or more atoms of different kinds
(iii)FalseOne molecule of nitrogen gas (N2) contains two nitrogen atoms
(iv)TrueWater (H2O) has two hydrogen atoms covalently bonded to one oxygen atom

Question 40: Formulae of aluminium nitrate, calcium oxide and ferric oxide

Q403 marks

Write the chemical formulae for the following compounds: (i) aluminium nitrate, (ii) calcium oxide, (iii) ferric oxide.

Answer
CompoundIonsBalancingFormula
(i) Aluminium nitrateAl3+, NO3−1 Al3+ needs 3 NO3−Al(NO3)3
(ii) Calcium oxideCa2+, O2−1 : 1CaO
(iii) Ferric oxideFe3+, O2−2 Fe3+ (6+) and 3 O2− (6−)Fe2O3

Question 41: Formulae from pairs of ions

Q412 marks

Write the formulae of the compounds formed from the following pairs of ions: (i) Ca2+ and Br−, (ii) Al3+ and CO32−, (iii) K+ and SO42−, (iv) NH4+ and Cl−.

Answer
IonsBalancingFormula
(i) Ca2+, Br−1 Ca2+ needs 2 Br−CaBr2
(ii) Al3+, CO32−2 Al3+ (6+) and 3 CO32− (6−)Al2(CO3)3
(iii) K+, SO42−2 K+ balance 1 SO42−K2SO4
(iv) NH4+, Cl−1 : 1NH4Cl

Question 42: Which diagram represents the Cl− ion?

Q423 marks

Which of the following in the figure correctly represents the Cl− ion (atomic number of chlorine = 17)?

Four atom diagrams (i), (ii), (iii) and (iv) with electron shells around a nucleus, to identify the Cl minus ion
Answer
  1. Neutral chlorine atom17 protons and 17 electrons; configuration 2, 8, 7.
  2. Cl− ionThe negative sign shows that it has gained 1 electron.Electrons = 17 + 1 = 18
  3. Electronic configuration2 electrons in the K shell, 8 in the L shell and 8 in the M shell: 2, 8, 8 (a full octet).

Diagram (ii), which shows 18 electrons, represents the Cl− ion.

Question 43: Formula unit mass of ammonium nitrate, phosphoric acid and sodium hydrogencarbonate

Q433 marks

Determine the formula unit mass of the following substances: (i) ammonium nitrate (NH4NO3), (ii) phosphoric acid (H3PO4), (iii) sodium hydrogencarbonate (NaHCO3). (Atomic mass: N = 14, H = 1, O = 16, P = 31, Na = 23, C = 12.)

Answer
SubstanceCalculationMass
(i) NH4NO3(2 × 14) + (4 × 1) + (3 × 16) = 28 + 4 + 4880 u
(ii) H3PO4(3 × 1) + 31 + (4 × 16) = 3 + 31 + 6498 u
(iii) NaHCO323 + 1 + 12 + (3 × 16) = 23 + 1 + 12 + 4884 u

Question 44: Formulae of compounds formed by metals and non-metals

Q442 marks

Write the formulae for the compounds formed by the reaction of: (i) magnesium and nitrogen, (ii) lithium and nitrogen, (iii) sodium and sulfur, (iv) aluminium and oxygen.

Answer
ReactionIonsBalancingFormula
(i) Mg and NMg2+, N3−3 Mg2+ (6+) and 2 N3− (6−)Mg3N2
(ii) Li and NLi+, N3−3 Li+ and 1 N3−Li3N
(iii) Na and SNa+, S2−2 Na+ and 1 S2−Na2S
(iv) Al and OAl3+, O2−2 Al3+ (6+) and 3 O2− (6−)Al2O3

Question 45: Table of compounds from cations and anions

Q453 marks

Complete the table by writing the formulae of the compounds formed by the cations on the left and the anions at the top. LiNO3 is given as an example.

NO3−SO42−PO43−
NH4+
Li+LiNO3
Al3+
Cu2+
Answer
NO3−SO42−PO43−
NH4+NH4NO3(NH4)2SO4(NH4)3PO4
Li+LiNO3Li2SO4Li3PO4
Al3+Al(NO3)3Al2(SO4)3AlPO4
Cu2+Cu(NO3)2CuSO4Cu3(PO4)2

Question 46: Verifying the law of conservation of mass: sodium carbonate and acetic acid

Q462 marks

5.3 g of sodium carbonate and 6.0 g of acetic acid react to produce 2.2 g of carbon dioxide, 0.9 g of water, and 8.2 g of sodium acetate. Verify whether the law of conservation of mass is valid.

Answer
SubstancesTotal mass
Reactants5.3 g + 6.0 g11.3 g
Products2.2 g + 0.9 g + 8.2 g11.3 g

Mass of reactants = mass of products, so the law of conservation of mass is valid.

Question 47: A species with 11 protons, 12 neutrons and 10 electrons

Q472 marks

If a species has 11 protons, 12 neutrons and 10 electrons, then (i) what is its atomic number and mass number? (ii) is it neutral, a cation or an anion? Explain. (iii) write its electronic configuration. (iv) name the species.

Answer
PartAnswerExplanation
(i)Atomic number = 11, mass number = 23Atomic number = protons; mass number = 11 + 12
(ii)Cation (charge +1)It has 11 protons but only 10 electrons, so it has lost one electron
(iii)2, 8It has 10 electrons in total
(iv)Sodium ion (Na+)Atomic number 11 is sodium, and it has lost 1 electron

Question 48: Reactivity and bonding of elements A (2, 8, 5) and B (2, 8, 7)

Q483 marks

Two elements, A and B, have the following configurations: A: 2, 8, 5 and B: 2, 8, 7. (i) Which element is more reactive? (ii) Will A and B form ionic or covalent bonds when they combine? Explain using electron transfer or sharing. (iii) Predict the formula of the compound they would form.

Answer
  • (i) B is more reactive, because it needs only 1 electron to complete its octet, while A needs 3.
  • (ii) A needs 3 electrons and B needs 1. Both are non-metals and neither can easily give up electrons, so they share electrons and form covalent bonds.
  • (iii) One A atom shares one electron with each of three B atoms, so the formula is AB3.

Question 49: Assertion-reason: conductivity of copper sulfate

Q491 mark

Assertion (A): Copper sulfate conducts electricity in the molten state but not in the solid state.

Reason (R): Copper and sulfate ions are fixed in the lattice in molten state, while in solid state they can move freely.

  1. Both A and R are true and R is the correct explanation of A.
  2. Both A and R are true but R is not the correct explanation of A.
  3. A is true but R is false.
  4. A is false but R is true.
Answer

Correct option: (c)

  • A is true: in the molten state the ions are free to move, so it conducts; in the solid state the ions are fixed.
  • R is false: it reverses the facts. In the solid state the ions are fixed in the lattice, and in the molten state they move freely.

Question 50: Electrons and neutrons in Al, Br− and Hg2+

Q503 marks

The species 27Al, 80Br− and 201Hg2+ have 13, 35 and 80 protons, respectively. How many electrons and neutrons do they have?

Answer
SpeciesProtonsElectronsNeutrons
27Al (neutral)131327 − 13 = 14
80Br− (gained 1 electron)3535 + 1 = 3680 − 35 = 45
201Hg2+ (lost 2 electrons)8080 − 2 = 78201 − 80 = 121

Question 51: Do any chemical changes break the law of conservation of mass?

Q512 marks

Are there any chemical changes that do not obey the Law of Conservation of Mass?

Answer

No. In every chemical reaction mass is conserved; it is neither created nor destroyed. Sometimes the mass seems to change because the reaction takes place in an open system, where gases can escape or enter. In a closed system, the total mass of the reactants is always equal to the total mass of the products.

Quick revision: Class 9 Science Chapter 9

  • Law of conservation of mass: mass is neither created nor destroyed in a chemical reaction. Law of constant (definite) proportions: a compound always has the same elements in a fixed ratio by mass.
  • A molecule is a group of atoms bonded together; an ion is a charged atom or group of atoms.
  • Ionic bond: electrons are transferred from a metal to a non-metal; ionic compounds conduct electricity when molten or dissolved.
  • Covalent bond: electrons are shared (single, double or triple bond); N2 has a triple bond and O2 a double bond.
  • To write a formula, balance the total positive and negative charges (criss-cross the charges).
  • Molecular mass or formula unit mass = sum of the atomic masses of all the atoms in the formula.
  • Noble gases have a complete outer shell (octet), so they are stable and do not form bonds.
  • Number of electrons = protons − charge of the ion; neutrons = mass number − atomic number.

Frequently asked questions

How many questions are solved in Class 9 Science Chapter 9?

All 51 questions of Chapter 9, Atomic Foundations of Matter, from the new NCERT Exploration textbook (2026-27) are solved on this page.

What is the difference between an ionic and a covalent bond?

In an ionic bond, electrons are transferred from one atom to another to form ions. In a covalent bond, atoms share pairs of electrons.

How do you write the chemical formula of a compound?

Write the symbols of the ions with their charges and balance the total positive charge and the total negative charge, for example, Al3+ and O2− give Al2O3.

How do you calculate the molecular mass of a compound?

Multiply the atomic mass of each element by the number of its atoms in the formula and add them up. For example, H2O = (2 × 1) + 16 = 18 u.

More free CBSE study material

Notes, worksheets, PPTs and practice papers for Classes 6 to 10 are available at uniquestudyonline.com.

Solutions prepared by Unique Study Point by Sumeet Sahu. Figures are from the NCERT Science textbook Exploration (Class 9).

๐Ÿ“‹ Details

ClassClass IX (CBSE / NCERT)
SubjectScience
ChapterChapter 9: Atomic Foundations of Matter
Resource TypeNCERT Solutions
Last Updated26 October 2026
Session2026-27 (Latest NCERT Syllabus)
Downloads1+
Prepared bySumeet Sahu, Unique Study Point, Indore
CostFree
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